Chapter 1, Problem 5E

To determine

To find: the value of $a+{\left(b+1\right)}^2$ .

Answer to Problem 5E

  $a+{\left(b+1\right)}^2=12$

Explanation of Solution

Given information:

Given values are

  $a=3,b=2$

Given option,

   A.$-6$

   B. $-1$

   C. $12$

   D.$15$

Calculation:

Consider the given expression.

  $a+{\left(b+1\right)}^2$

Here, value of a is 3.

The expression is sum of two positive number.

So, value cannot be negative.

Therefore, option A and B are incorrect.

Now, evaluate the expression by substituting $a=3,b=2$ :

  $\begin{array}{c}a+{\left(b+1\right)}^2=3+{\left(2+1\right)}^2\\ =3+3^2\\ =3+9\\ =12\end{array}$

So, the correct option is C.