Interpretation Introduction Interpretation: The given table is to be completed: ( a ) 1245 k g 1.245 × 10 6 g 1.245 × 10 9 m g ( b ) 515 k m _ d m _ c m ( c )12 2.355 s _ m s _ k s ( d ) 3.345 k J _ J _ m J Explanation Solving Row 1 1245 kg 1245 kg in scientific notation in units of grams is written as: 1 kg = 10 3 g Thus, multiply the given measurement with a base unit, 1 × 10 3 g to get, 1245 k g = 1245 × 1 × 10 3 g = 1245 × 10 3 g o r 1.245 × 10 6 g Hence, 1245 kg in scientific notation in units of grams is written as 1.245 × 10 6 g . 1.245 × 10 6 g in scientific notation in units of milligrams is written as: 1kg = 10 6 mg Thus, multiply the given measurement with a base unit, 1 × 10 6 mg to get, 1245 k g = 1245 × 1 × 10 6 mg = 1245 × 10 6 mg o r 1.245 × 10 9 mg Hence, 1245 kg in scientific notation in units of milligrams is written as 1.245 × 10 9 mg . Solving Row 1 515 km 515 km in scientific notation in units of decimeters is written as: 1 km = 10 3 m and 1m = 10 dm, thus, 1 km = 10 4 dm Thus, multiply the given measurement with a base unit, 1 × 10 4 dm to get, 515 k m = 515 × 1 × 10 4 dm = 515 × 10 4 dm o r 5.15 × 10 6 dm Hence, 515 km in scientific notation in units of decimeters is written as 5.15 × 10 6 dm . 515 km in scientific notation in units of centimeters is written as: 1 km = 10 3 m and 1m = 10 2 cm, thus, 1 km = 10 5 cm Thus, multiply the given measurement with a base unit, 1 × 10 5 cm to get, 515 k m = 515 × 1 × 10 5 cm = 515 × 10 5 cm o r 5.15 × 10 7 cm Hence, 515 km in scientific notation in units of centimeters is written as 5

Chemistry: A Molecular Approach (4th Edition)

4th Edition

ISBN: 9780134112831

Author: Nivaldo J. Tro

Publisher: PEARSON

See similar textbooks

Concept explainers

Matter and Measurement

In the universe, there is matter, energy, and void space. The universe contains energy and void space. The definition of matter can be considered as something which possesses mass and consumes space. Chemistry is that branch of science which deals with t…

Videos

Question

Chapter 1, Problem 59E

Interpretation Introduction

Interpretation: The given table is to be completed:

(a) 1245 kg 1.245×106 g 1.245×109 mg (b) 515 km _ dm _ cm (c)122.355 s _ms _ ks (d) 3.345 kJ _J _ mJ

Expert Solution & Answer

Chapter 1 Solutions

Chemistry: A Molecular Approach (4th Edition)

Ch. 1 - A chemist mixes sodium with water and witnesses a...Ch. 1 - Q2. This image represents a particulate view of a...Ch. 1 - Which change is a physical change? a) Wood burning...Ch. 1 - Q4. Which property of rubbing alcohol is a...Ch. 1 - Convert 85F to K. a) 181.1 K b) 358 K c) 29.4 K d)...Ch. 1 - Express the quantity 33.2 10?4 m in mm. a) 33.2...Ch. 1 - Q7. What is the mass of a 1.75 L sample of a...Ch. 1 - Perform the calculation to the correct number of...Ch. 1 - Q9. Perform the calculation to the correct number...Ch. 1 - Q10. Convert 1285 cm2 to m2. a) 1.285 × 107...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

The given table is to be completed: ( a ) 1245 k g 1.245 × 10 6 g 1.245 × 10 9 m g ( b ) 515 k m _ d m _ c m ( c )12 2.355 s _ m s _ k s ( d ) 3.345 k J _ J _ m J

Concept explainers

Videos

Interpretation: The given table is to be completed: (a) 1245 kg 1.245×106 g 1.245×109 mg (b) 515 km _ dm _ cm (c)122.355 s _ms _ ks (d) 3.345 kJ _J _ mJ

Chapter 1 Solutions

Interpretation: The given table is to be completed:

(a) 1245 kg 1.245×106 g 1.245×109 mg (b) 515 km _ dm _ cm (c)122.355 s _ms _ ks (d) 3.345 kJ _J _ mJ