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EBK ESSENTIALS OF MIS,
13th Edition
ISBN: 8220106778494
Author: LAUDON
Publisher: PEARSON
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Expert Solution & Answer
Chapter 1, Problem 4IQ
Explanation of Solution
Working with Clients:
There’s a lot of negative press coverage for companies that deliver poor customer service and if one wants t...
Explanation of Solution
Client Service or support:
One can have excellent customer service or support while working with clients in the following ways:
- One of the biggest factors in good customer service is speed, especially when a client is requesting something that’s time sensitive.
For example, Lexus recalled a series of Lexus ES 350 sedans and asked car owners to visit a dealership to bring their cars in and instead of having to sit in a waiting room watching their cars being worked on; customers were given a brand new Lexus instead.
- For good customer service, one must always know their customers and must remember their names and previous conversations.
For example, when Starbucks launched a new campaign focusing on improving relationships between their staff and customers, each person who introduced themselves by name received a free latte...
Expert Solution & Answer
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Students have asked these similar questions
7. See the code below and solve the following.
public class Test {
public static void main(String[] args) {
int result = 0;
}
result = fn(2,3);
System.out.println("The result is:
+ result);
// fn(x, 1) = x
// fn(x, y)
=
fn(x, y-1) + 2, when y>1
public static int fn(int x, int y) {
if (x <= 1)
return x;
else
return fn(x, y-1) + 2;
}
}
7-1. This program has a bug that leads to infinite recursion. Modify fn(int x, int y) method to fix
the problem. (2 point)
7-2. Manually trace the recursive call, fn(2,3) and show the output (step by step). (2 point)
7-3. Can you identify the Base Case in recursive method fn(int x, int y)? (1 point)
6. See the code below and solve the following.
import java.io.*;
public class DataStream {
}
public static void main(String[] args)
}
DataOutputStream output = new DataOutputStream(new FileOutputStream("temp.dat"));
output.writeUTF("Book1");
output.writeInt(85);
output.writeUTF("Book2");
output.writeInt(125);
output.writeUTF("Book3");
output.writeInt(70);
output.close();
// ToDo: Read all data from temp.dat and print the data to the standard output (monitor)
6-1. This program has a compile error, and the message is “Unhandled exception type
FileNotFoundException". How do you fix this error? (1 point)
6-2. Is FileNotFoundException a checked exception or an unchecked exception? (1 point)
6-3. What is the difference between checked exception and unchecked exception? (1 point)
6-4. Please complete the above program by reading all data from temp.dat and print the data
to the standard output (monitor) by using System.out.print, System.out.println or
System.out.printf method. (2 points)
Write a program that reads a list of integers from input and determines if the list is a palindrome (values are identical from first to last and last to first). The input begins with an integer indicating the length of the list that follows. Assume the list will contain a maximum of 20 integers. Output "yes" if the list is a palindrome and "no" otherwise. The output ends with a newline.
Hints: - use a for loop to populate the array based on the specified size (the first number entered)
- use a for loop to check first value with last value, second value with second from end, etc.
- if the values do not match, set a Boolean variable to flag which statement to output (yes or no)
Ex: If the input is (remember to include spaces between the numbers):
6 1 5 9 9 5 1
the output is:
yes
Ex: If the input is:
5 1 2 3 4 5
the output is: C++ coding
Chapter 1 Solutions
EBK ESSENTIALS OF MIS,
Ch. 1.1 - Prob. 1CQ1Ch. 1.1 - Prob. 2CQ1Ch. 1.1 - Prob. 3CQ1Ch. 1.1 - Prob. 4CQ1Ch. 1.2 - Prob. 1CQ2Ch. 1.2 - Prob. 2CQ2Ch. 1.2 - Prob. 3CQ2Ch. 1.2 - Prob. 4CQ2Ch. 1 - Prob. 1IQCh. 1 - Prob. 2IQ
Ch. 1 - Prob. 3IQCh. 1 - Prob. 4IQCh. 1 - Prob. 5IQCh. 1 - Prob. 1RQCh. 1 - Prob. 2RQCh. 1 - Prob. 3RQCh. 1 - Prob. 4RQCh. 1 - Prob. 5DQCh. 1 - Prob. 6DQCh. 1 - Prob. 7DQCh. 1 - Prob. 8HMPCh. 1 - Prob. 9HMPCh. 1 - Prob. 11HMPCh. 1 - Prob. 12CTPCh. 1 - Prob. 13CSQCh. 1 - Prob. 14CSQCh. 1 - Prob. 15CSQCh. 1 - Prob. 16CSQCh. 1 - Prob. 17MLMCh. 1 - Prob. 18MLM
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