(a) Interpretation: The boiling point of water in A 0 if melting point of ammonia is 0 A 0 or − 77.75 C 0 and boiling point of ammonia is 100 A 0 or - 33.35 C 0 needs to be determined. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing the different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o A ) – T lower ( in o A ) ) ( T higher ( in o A ) – T lower ( in o A ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )
(a) Interpretation: The boiling point of water in A 0 if melting point of ammonia is 0 A 0 or − 77.75 C 0 and boiling point of ammonia is 100 A 0 or - 33.35 C 0 needs to be determined. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing the different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o A ) – T lower ( in o A ) ) ( T higher ( in o A ) – T lower ( in o A ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )
Solution Summary: The author explains the conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The boiling point of water in A0 if melting point of ammonia is 0 A0 or − 77.75 C0 and boiling point of ammonia is 100 A0 or - 33.35 C0 needs to be determined.
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oA)– Tlower(in oA))(Thigher( in oA)– Tlower(in oA)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
Interpretation Introduction
(b)
Interpretation:
The absolute zero temperature in A0 needs to be determined, if melting point of ammonia is 0 A0 or − 77.75 C0 and boiling point of ammonia is 100 A0 or - 33.35 C0
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oA)– Tlower(in oA))(Thigher( in oA)– Tlower(in oA)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
In the solid state, oxalic acid occurs as
a dihydrate with the formula H2C2O4
C+2H2O. Use this formula to
calculate the formula weight of oxalic
acid. Use the calculated formula
weight and the number of moles
(0.00504mol)
of oxalic acid in each titrated
unknown sample recorded in Table
6.4 to calculate the number of grams
of pure oxalic acid dihydrate
contained in each titrated unknown
sample.
1.
Consider a pair of elements with 2p and 4p valence orbitals (e.g., N and Se). Draw their
(2p and 4p AO's) radial probability plots, and sketch their angular profiles. Then, consider these
orbitals from the two atoms forming a homonuclear л-bond. Which element would have a
stronger bond, and why?
(4 points)
Write the reaction and show the mechanism of the reaction. Include the mechanism
for formation of the NO2+
2. Explain, using resonance structures, why the meta isomer is formed. Draw possible
resonance structures for ortho, meta and para.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell