(a) Interpretation: The boiling point of water in A 0 if melting point of ammonia is 0 A 0 or − 77.75 C 0 and boiling point of ammonia is 100 A 0 or - 33.35 C 0 needs to be determined. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing the different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o A ) – T lower ( in o A ) ) ( T higher ( in o A ) – T lower ( in o A ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )
(a) Interpretation: The boiling point of water in A 0 if melting point of ammonia is 0 A 0 or − 77.75 C 0 and boiling point of ammonia is 100 A 0 or - 33.35 C 0 needs to be determined. Concept introduction: The conversion factor required to determine the results in different or desired scale by equivalizing the different units. The temperature of the sample at given scale degree M can be identified as follows: ( T calculated ( in o A ) – T lower ( in o A ) ) ( T higher ( in o A ) – T lower ( in o A ) ) = ( T calculated ( in o C ) – T lower ( in o C ) ) ( T higher ( in o C ) – T lower ( in o C ) )
Solution Summary: The author explains the conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The boiling point of water in A0 if melting point of ammonia is 0 A0 or − 77.75 C0 and boiling point of ammonia is 100 A0 or - 33.35 C0 needs to be determined.
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oA)– Tlower(in oA))(Thigher( in oA)– Tlower(in oA)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
Interpretation Introduction
(b)
Interpretation:
The absolute zero temperature in A0 needs to be determined, if melting point of ammonia is 0 A0 or − 77.75 C0 and boiling point of ammonia is 100 A0 or - 33.35 C0
Concept introduction:
The conversion factor required to determine the results in different or desired scale by equivalizing the different units.
The temperature of the sample at given scale degree M can be identified as follows:
(Tcalculated(in oA)– Tlower(in oA))(Thigher( in oA)– Tlower(in oA)) = (Tcalculated( in oC)– Tlower(in oC))(Thigher(in oC)– Tlower( in oC))
Complete combustion of a 0.6250 g sample of the unknown crystal with excess O2 produced 1.8546 g of CO2 and 0.5243 g of H2O. A separate analysis of a 0.8500 g sample of the blue crystal was found to produce 0.0465 g NH3. The molar mass of the substance was found to be about 310 g/mol. What is the molecular formula of the unknown crystal?
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell