Foundations of Astronomy (MindTap Course List)
Foundations of Astronomy (MindTap Course List)
14th Edition
ISBN: 9781337399920
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 1, Problem 3SOP

The Sun is roughly 100 times the diameter of Earth. Which of the following distances is roughly 100 times the diameter of the Sun? radius of the Milky Way Galaxy; radius of the Moon; radius of Earth’s orbit around the Sun; radius of the Moon’s orbit around Earth

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The radius of the Earth's orbit is 1.50  1011 m and that of Mars is 2.28  1011 m. The star that this planet orbits is identical to our Sun. What is the orbital period of this planet?In years?
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It is important to have an idea about the distances between and relative sizes of celestial objects in the solar system. In Part 1 we will pretend to shrink the solar system until its center piece, the Sun, is 67.3 cm in diameter. This will represent the Sun which is 1,390,000 km in diameter. The scale of our model is thus: 67.3 cm = 4.84 x 10-5 cm km Scale 1, 390, 000 km To find the size or distance between objects in centimeters for the model, simply multiply the actual size or distance in kilometers by the scale factor above. 1. Fill in following table: Quantity Actual Distance (km) Model Distance (cm) Diameter of Sun 1,390,000 Diameter of Earth 12,760 Diameter of Moon 3,480 Distance Between Earth and Sun 1.5 x 108 Distance Between Earth and Moon 384,000 Distance to Proxima Centauri 3.97 x 1013

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Foundations of Astronomy (MindTap Course List)

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