21ST CENT.ASTRONOMY(LL)W/CODE WKBK PKG.
21ST CENT.ASTRONOMY(LL)W/CODE WKBK PKG.
6th Edition
ISBN: 9780393874921
Author: PALEN
Publisher: Norton, W. W. & Company, Inc.
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Chapter 1, Problem 37QP

(a)

To determine

The time that takes for light from Neptune to reach Earth.

(b)

To determine

The problem when conducting tow-way conversation from Neptune to Earth.

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Suppose you send a probe to land on Mercury, and the probe transmits radio signals to earth at a wavelength of 52.0000 cm. You listen for the probe when Mercury is moving away from Earth at its full orbital velocity of 48 km/s around the Sun. What wavelength (in cm) would you have to tune your radio telescope to detect that signal? Use the doppler shift formula  Note: the speed of light is 3.0 ✕ 105 km/s. Give your answer to at least four decimal places.)
Calculate how long radio communications from the spacecraft will take when it encounters Mars.  The furthest distance from Earth to Mars is 2.66 AU.  Remember that 1 AU = 1.5 x 1011 m and that light travels at 3 x 108 m/s.  So how long will the radio messages take to travel this greatest distance of 2.66 AU?           If two way communication between the Earth and the spacecraft involve a 1 s time lapse before an acknowledging signal is sent by the spacecraft, how long a time is there between sending a command to the spacecraft and receiving a reply?
The planet Mercury is closer to the Sun than the Earth is, so it can sometimes come between Earth and Sun. That's called a transit. A transit is like a failed solar eclipse: In a solar eclipse, the Moon gets between Earth and Sun and blocks all sunlight. In a transit, Mercury blocks only a small fraction of the Sun's light because Mercury isn't close enough to us to completely block our view of the Sun.     We want to calculate by how much the Sun will be dimmed when such a transit occurs, because that's important to know for satellites which are powered by solar panels (shown hovering around the Earth in the image above). Without Mercury in the way, the radiation intensity that hits the top of the Earth's atmosphere from the Sun is 1,360.8 W/m2  (W stands for Watt, measuring energy transferred per second).  The fraction of this intensity that is blocked by Mercury during a transit is equal to the ratio between the cross-sectional area of Mercury (as seen from Earth) and the…
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