Essential Organic Chemistry (3rd Edition)
Essential Organic Chemistry (3rd Edition)
3rd Edition
ISBN: 9780321937711
Author: Paula Yurkanis Bruice
Publisher: PEARSON
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Textbook Question
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Chapter 1, Problem 37P

Draw a Lewis structure for each of the following species:

  1. a. H2CO3
  2. b. CO32−
  3. c. CH2O
  4. d. CO2

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

Lewis structure of H2CO3 has to be drawn.

Concept Introduction:

A Lewis dot structure for an atom consists of a symbol for the element and one dot for each valence electron.

Steps in drawing a Lewis dot structure,

  • Total number of valence electron has to be known.
  • Atoms has to be distributed by the knowing the valency of each atom.
  • Form bonds and fill the octet with lone pair of electrons.
  • Formal charge if present has to be assigned.

Explanation of Solution

Given compound is H2CO3.

Number of valence electron of each atoms is identified and drawn as below,

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  1

Hydrogen can form only one bond, carbon can form four bonds and oxygen has six valence electrons.

Atoms have to be distributed by putting hydrogen on outside the molecule.

Here, there are two oxygen atoms, so avoiding the oxygen-oxygen single bonds.

The Lewis structure can be,

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  2 or Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  3

Each atom has to achieve an octet and the existing electron has to be shared.

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

Lewis structure of CO32 has to be drawn.

Concept Introduction:

A Lewis dot structure for an atom consists of a symbol for the element and one dot for each valence electron.

Steps in drawing a Lewis dot structure,

  • Total number of valence electron has to be known.
  • Atoms has to be distributed by the knowing the valency of each atom.
  • Form bonds and fill the octet with lone pair of electrons.
  • Formal charge if present has to be assigned.

Explanation of Solution

Given compound is CO32.

Number of valence electron of each atoms is identified and drawn as below,

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  4

Carbon can form four bonds and oxygen has six valence electrons.

Atoms have to be distributed by putting hydrogen on outside the molecule.

Here, there are two oxygen atoms, so avoiding the oxygen-oxygen single bonds.

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  5 or Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  6

Each atom has to achieve an octet and the existing electron has to be shared.

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

Lewis structure of H2CO has to be drawn.

Concept Introduction:

A Lewis dot structure for an atom consists of a symbol for the element and one dot for each valence electron.

Steps in drawing a Lewis dot structure,

  • Total number of valence electron has to be known.
  • Atoms has to be distributed by the knowing the valency of each atom.
  • Form bonds and fill the octet with lone pair of electrons.
  • Formal charge if present has to be assigned.

Explanation of Solution

Given compound is H2CO.

Number of valence electron of each atoms is identified and drawn as below,

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  7

Hydrogen can form only one bond, carbon can form four bonds and oxygen has six valence electrons.

Atoms have to be distributed by putting hydrogen on outside the molecule.

Here, there are two oxygen atoms, so avoiding the oxygen-oxygen single bonds.

The Lewis structure can be,

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  8 or Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  9

Each atom has to achieve an octet and the existing electron has to be shared.

(d)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

Lewis structure of CO2 has to be drawn.

Concept Introduction:

A Lewis dot structure for an atom consists of a symbol for the element and one dot for each valence electron.

Steps in drawing a Lewis dot structure,

  • Total number of valence electron has to be known.
  • Atoms has to be distributed by the knowing the valency of each atom.
  • Form bonds and fill the octet with lone pair of electrons.
  • Formal charge if present has to be assigned.

Explanation of Solution

Given compound is CO2.

Number of valence electron of each atoms is identified and drawn as below,

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  10

Carbon can form four bonds and oxygen has six valence electrons.

Atoms have to be distributed by putting hydrogen on outside the molecule.

Here, there are two oxygen atoms, so avoiding the oxygen-oxygen single bonds.

Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  11 or Essential Organic Chemistry (3rd Edition), Chapter 1, Problem 37P , additional homework tip  12

Each atom has to achieve an octet and the existing electron has to be shared.

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Chapter 1 Solutions

Essential Organic Chemistry (3rd Edition)

Ch. 1.4 - Prob. 12PCh. 1.4 - a. Draw two Lewis structures for C2H6O. b. Draw...Ch. 1.4 - Draw the lone-pair electrons that are not shown in...Ch. 1.4 - Prob. 16PCh. 1.4 - Which of the atoms in the molecular models in...Ch. 1.4 - Prob. 18PCh. 1.7 - What orbitals are used to form the 10 sigma bonds...Ch. 1.9 - Put a number in each of the blanks: a. ___ s...Ch. 1.11 - Predict the approximate bond angles in a. the...Ch. 1.11 - According to the potential map for the ammonium...Ch. 1.12 - Prob. 25PCh. 1.13 - a. Predict the relative lengths and strengths of...Ch. 1.13 - Prob. 28PCh. 1.14 - Which of the bonds in a carbonoxygen double bond...Ch. 1.14 - Caffeine is a natural insecticide, found in the...Ch. 1.14 - a. What is the hybridization of each of the carbon...Ch. 1.14 - Prob. 33PCh. 1.14 - Describe the orbitals used in bonding and the bond...Ch. 1.15 - Account for the difference in the shape and color...Ch. 1.15 - Which of the following molecules would you expect...Ch. 1 - Draw a Lewis structure for each of the following...Ch. 1 - Prob. 38PCh. 1 - What is the hybridization of all the atoms (other...Ch. 1 - Prob. 40PCh. 1 - Draw the condensed structure of a compound that...Ch. 1 - Prob. 42PCh. 1 - Prob. 43PCh. 1 - Draw a Lewis structure for each of the following...Ch. 1 - Prob. 45PCh. 1 - List the bonds in order from most polar to least...Ch. 1 - What is the hybridization of the indicated atom in...Ch. 1 - Write the Kekul structure for each of the...Ch. 1 - Assign the missing formal charges.Ch. 1 - Predict the approximate bond angles for the...Ch. 1 - Prob. 51PCh. 1 - a. Which of the indicated bonds in each compound...Ch. 1 - In which orbitals are the lone pairs in nicotine?...Ch. 1 - Draw the missing lone-pair electrons and assign...Ch. 1 - Rank the following compounds from highest dipole...Ch. 1 - Prob. 56PCh. 1 - a. Which of the species have bond angles of 109.5?...Ch. 1 - Prob. 58PCh. 1 - Sodium methoxide (CH3ONa) has both ionic and...Ch. 1 - a. Why is a H 8 H bond (0.74 ) shorter than a C 8...Ch. 1 - Which compound has a larger dipole moment, CHCl3...Ch. 1 - Which compound has a longer C 8 Cl bond?Ch. 1 - Prob. 63PCh. 1 - The following compound has two isomers. One isomer...

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