Concept explainers
a.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangement of atoms in the molecule are said to be isomers of each other.
a.
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Answer to Problem 32PP
Explanation of Solution
For the first isomer structure, all two-carbon atoms are written in a straight chain and the chlorine atom is bonded to one of the carbon atoms as:
There is no other possibility for the different structural formula
b.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangement of atoms in the molecule are said to be isomers of each other.
b.
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Answer to Problem 32PP
Isomer I:
Isomer II:
Explanation of Solution
The different structural the arrangement of atoms in the molecule
- All two-carbon atoms are written in a straight chain and two chlorine atoms are bonded to one of the carbon atoms resulting in:
- Interchanging the position of one hydrogen atom at first carbon with one chlorine atom of the second carbon atom.
Isomer I:
Isomer II:
c.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangements of atoms in the molecule are said to be isomers of each other.
c.
![Check Mark](/static/check-mark.png)
Answer to Problem 32PP
Isomer I:
Isomer II:
Explanation of Solution
The different structural arrangement of atoms in the molecule
- All two-carbon atoms are written in a straight chain and three chlorine atoms are bonded to one of the carbon atoms resulting in:
- Interchanging the position of one hydrogen atom at first carbon with one chlorine atom of the second carbon atom.
Isomer I:
Isomer II:
d.
Interpretation: All the constitutional isomers that have molecular formulas
Concept Introduction: The molecules that possess the same molecular formula but differ in the structural arrangements of atoms in the molecule are said to be isomers of each other.
d.
![Check Mark](/static/check-mark.png)
Answer to Problem 32PP
Isomer I:
Isomer II:
Isomer III:
Isomer IV:
Isomer V:
Explanation of Solution
The different structural arrangement of atoms in the molecule
- All six-carbon atoms are written in a straight chain resulting in:
- Five-carbon atoms are written in a straight chain and a methyl group is attached to the second carbon resulting in:
- Five-carbon atoms are written in a straight chain and a methyl group is attached to the third carbon resulting in:
- Four-carbon atoms are written in a straight chain and a methyl group is attached to the second and third carbon resulting in:
- Four-carbon atoms are written in a straight chain and two methyl groups are attached to the second carbon resulting in:
Isomer I:
Isomer II:
Isomer III:
Isomer IV:
Isomer V:
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Chapter 1 Solutions
ORGANIC CHEMISTRY-PRINT MULTI TERM
- 5) Confidence interval. Berglund and Wichardt investigated the quantitative determination of Cr in high-alloy steels using a potentiometric titration of Cr(VI). Before the titration, samples of the steel were dissolved in acid and the chromium oxidized to Cr(VI) using peroxydisulfate. Shown here are the results (as %w/w Cr) for the analysis of a reference steel. 16.968, 16.922, 16.840, 16.883, 16.887, 16.977, 16.857, 16.728 Calculate the mean, the standard deviation, and the 95% confidence interval about the mean. What does this confidence interval mean?arrow_forwardIn the Nitrous Acid Test for Amines, what is the observable result for primary amines? Group of answer choices nitrogen gas bubbles form a soluble nitrite salt yellow oily layer of nitrosoaminearrow_forward3. a. Use the MS to propose at least two possible molecular formulas. For an unknown compound: 101. 27.0 29.0 41.0 50.0 52.0 55.0 57.0 100 57.5 58.0 58.5 62.0 63.0 64.0 65.0 74.0 40 75.0 76.0 20 20 40 60 80 100 120 140 160 180 200 220 m/z 99.5 68564810898409581251883040 115.0 116.0 77404799 17417M 117.0 12.9 118.0 33.5 119.0 36 133 0 1.2 157.0 2.1 159.0 16 169.0 219 170.0 17 171.0 21.6 172.0 17 181.0 1.3 183.0 197.0 100.0 198.0 200. 784 Relative Intensity 2 2 8 ō (ppm) 6 2arrow_forward
- Solve the structure and assign each of the following spectra (IR and C-NMR)arrow_forward1. For an unknown compound with a molecular formula of C8H100: a. What is the DU? (show your work) b. Solve the structure and assign each of the following spectra. 8 6 2 ō (ppm) 4 2 0 200 150 100 50 ō (ppm) LOD D 4000 3000 2000 1500 1000 500 HAVENUMBERI -11arrow_forward16. The proton NMR spectral information shown in this problem is for a compound with formula CioH,N. Expansions are shown for the region from 8.7 to 7.0 ppm. The normal carbon-13 spec- tral results, including DEPT-135 and DEPT-90 results, are tabulated: 7 J Normal Carbon DEPT-135 DEPT-90 19 ppm Positive No peak 122 Positive Positive cus и 124 Positive Positive 126 Positive Positive 128 No peak No peak 4° 129 Positive Positive 130 Positive Positive (144 No peak No peak 148 No peak No peak 150 Positive Positive してしarrow_forward
- 3. Propose a synthesis for the following transformation. Do not draw an arrow-pushing mechanism below, but make sure to draw the product of each proposed step (3 points). + En CN CNarrow_forwardShow work..don't give Ai generated solution...arrow_forwardLabel the spectrum with spectroscopyarrow_forward
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
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