21st Century Astronomy 6E
6th Edition
ISBN: 9780393690675
Author: Laura Kay, Stacy Palen, George Blumenthal
Publisher: W. W. Norton
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Chapter 1, Problem 2QP
To determine
The time takes for light from Sun to reach Earth.
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The figure shows a particle that carries a charge of 90 = -2.50 × 106 C. It is moving along the +y
->
axis at a speed of v = 4.79 × 106 m/s. A magnetic field B of magnitude 3.24 × 10-5 T is directed
along the +z axis, and an electric field E of magnitude 127 N/C points along the -x axis.
Determine (a) the magnitude and (b) direction (as an angle within x-y plane with respect to +x-
axis in the range (-180°, 180°]) of the net force that acts on the particle.
+x
+z
AB
90
+y
Three charged particles are located at the corners of an equilateral triangle as shown in the figure below (let q = 1.00 μC, and L = 0.850 m). Calculate the total electric force on the 7.00-μC charge.
magnitude
direction
N
° (counterclockwise from the +x axis)
y
7.00 με
9
L
60.0°
x
-4.00 μC ①
(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 9.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.
(b) Imagine adding electrons to the pin until the negative charge has the very large value 1.00 mC. How many electrons are added for every 109 electrons already present?
Chapter 1 Solutions
21st Century Astronomy 6E
Ch. 1.1 - Prob. 1.1CYUCh. 1.2 - Prob. 1.2CYUCh. 1.3 - Prob. 1.3CYUCh. 1 - Prob. 1QPCh. 1 - Prob. 2QPCh. 1 - Prob. 3QPCh. 1 - Prob. 4QPCh. 1 - Prob. 5QPCh. 1 - Prob. 6QPCh. 1 - Prob. 7QP
Ch. 1 - Prob. 8QPCh. 1 - Prob. 9QPCh. 1 - Prob. 10QPCh. 1 - Prob. 11QPCh. 1 - Prob. 12QPCh. 1 - Prob. 13QPCh. 1 - Prob. 14QPCh. 1 - Prob. 15QPCh. 1 - Prob. 16QPCh. 1 - Prob. 17QPCh. 1 - Prob. 18QPCh. 1 - Prob. 19QPCh. 1 - Prob. 20QPCh. 1 - Prob. 21QPCh. 1 - Prob. 22QPCh. 1 - Prob. 23QPCh. 1 - Prob. 24QPCh. 1 - Prob. 25QPCh. 1 - Prob. 26QPCh. 1 - Prob. 27QPCh. 1 - Prob. 28QPCh. 1 - Prob. 29QPCh. 1 - Prob. 30QPCh. 1 - Prob. 31QPCh. 1 - Prob. 32QPCh. 1 - Prob. 33QPCh. 1 - Prob. 34QPCh. 1 - Prob. 35QPCh. 1 - Prob. 36QPCh. 1 - Prob. 37QPCh. 1 - Prob. 38QPCh. 1 - Prob. 39QPCh. 1 - Prob. 40QPCh. 1 - Prob. 41QPCh. 1 - Prob. 42QPCh. 1 - Prob. 43QPCh. 1 - Prob. 44QPCh. 1 - Prob. 45QP
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- (a) A physics lab instructor is working on a new demonstration. She attaches two identical copper spheres with mass m = 0.180 g to cords of length L as shown in the figure. A Both spheres have the same charge of 6.80 nC, and are in static equilibrium when 0 = 4.95°. What is L (in m)? Assume the cords are massless. 0.180 Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the spheres. Find an equation for the distance between the two spheres in terms of L and 0, and use this expression in your Coulomb force equation. m (b) What If? The charge on both spheres is increased until each cord makes an angle of 0 = 9.90° with the vertical. If both spheres have the same electric charge, what is the charge (in nC) on each sphere in this case? 9.60 Use the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. ncarrow_forwardA proton moves at 5.20 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 8.40 × 103 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 6.00 cm horizontally. 83.33 Your response differs from the correct answer by more than 10%. Double check your calculations. ns (b) Find its vertical displacement during the time interval in which it travels 6.00 cm horizontally. (Indicate direction with the sign of your answer.) 2.77 Your response differs from the correct answer by more than 10%. Double check your calculations. mm (c) Find the horizontal and vertical components of its velocity after it has traveled 6.00 cm horizontally. = 5.4e5 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. I + 6.68e4 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step…arrow_forward(a) A physics lab instructor is working on a new demonstration. She attaches two identical copper spheres with mass m = 0.180 g to cords of length L as shown in the figure. A Both spheres have the same charge of 6.80 nC, and are in static equilibrium when = 4.95°. What is L (in m)? Assume the cords are massless. 0.150 Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the spheres. Find an equation for the distance between the two spheres in terms of L and 0, and use this expression in your Coulomb force equation. m (b) What If? The charge on both spheres is increased until each cord makes an angle of 0 = 9.90° with the vertical. If both spheres have the same electric charge, what is the charge (in nC) on each sphere in this case? 13.6 ☑ Use the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. nCarrow_forward
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- Please help me solve this one more detail, thanksarrow_forwardA dielectric-filled parallel-plate capacitor has plate area A = 20.0 ccm2 , plate separaton d = 10.0 mm and dielectric constant k = 4.00. The capacitor is connected to a battery that creates a constant voltage V = 12.5 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 . Find the energy U1 of the dielectric-filled capacitor. The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2 of the capacitor at the moment when the capacitor is half-filled with the dielectric. The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3. In the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work W is done by the external agent acting on the dielectric?arrow_forwardIn (Figure 1) C1 = 6.00 μF, C2 = 6.00 μF, C3 = 12.0 μF, and C4 = 3.00 μF. The capacitor network is connected to an applied potential difference Vab. After the charges on the capacitors have reached their final values, the voltage across C3 is 40.0 V. What is the voltage across C4? What is the voltage Vab applied to the network? Please explain everything in steps.arrow_forward
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