Bundle: Enhanced Discovering Computers ©2017, Loose-leaf Version + LMS Integrated MindTap Computing, 1 term (6 months) Printed Access Card
1st Edition
ISBN: 9781337351911
Author: Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell
Publisher: Cengage Learning
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Question
Chapter 1, Problem 2IR
Program Plan Intro
Online Social Networks:
- It is an online platform used by people to build social networks or for maintaining social relationship with other people.
- It is mainly used for linking people, organization and knowledge.
- It allows users to share photos, videos and also allows people to share real world activities with people in their network.
Explanation of Solution
Type of advertisements featured in social networking sites:
- Common types of ads used in these social networking sites are:
- Lead ads
- It is the proce...
- Lead ads
Explanation of Solution
Sites for older and younger users:
- According to a study facebook is for older people. Most percent of teens are using this for popularity...
Explanation of Solution
Online social networks for business:
- The various social networking sites used for business are facebook, insta...
Explanation of Solution
Companies using social networking site as a recruiting tool:
- The companies ...
Explanation of Solution
Native languages supported:
- Facebook is available with 70 official languages...
Explanation of Solution
Professionals using social networking sites:
- Social networking sites find potential clients and business partners by...
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#include
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1. [20 pts] What is the output of the program? Please explain why.
2. [15 pts] What is the gdb command to set a breakpoint in line 6 (p
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3. [15 pts] Explain in your own words how the [break.
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Please run and debug the following program and answer the questions.
(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
Chapter 1 Solutions
Bundle: Enhanced Discovering Computers ©2017, Loose-leaf Version + LMS Integrated MindTap Computing, 1 term (6 months) Printed Access Card
Ch. 1 - Prob. 1SGCh. 1 - Prob. 2SGCh. 1 - Prob. 3SGCh. 1 - Prob. 4SGCh. 1 - Prob. 5SGCh. 1 - Prob. 6SGCh. 1 - Prob. 7SGCh. 1 - Prob. 8SGCh. 1 - Prob. 9SGCh. 1 - Prob. 10SG
Ch. 1 - Prob. 11SGCh. 1 - Prob. 12SGCh. 1 - Prob. 13SGCh. 1 - Prob. 14SGCh. 1 - Prob. 15SGCh. 1 - Prob. 16SGCh. 1 - Prob. 17SGCh. 1 - Prob. 18SGCh. 1 - Prob. 19SGCh. 1 - Prob. 20SGCh. 1 - Prob. 21SGCh. 1 - Prob. 22SGCh. 1 - Prob. 23SGCh. 1 - Prob. 24SGCh. 1 - Prob. 25SGCh. 1 - Prob. 26SGCh. 1 - Prob. 27SGCh. 1 - Prob. 28SGCh. 1 - Prob. 29SGCh. 1 - Prob. 30SGCh. 1 - Prob. 31SGCh. 1 - Prob. 32SGCh. 1 - Prob. 33SGCh. 1 - Prob. 34SGCh. 1 - Prob. 35SGCh. 1 - Prob. 36SGCh. 1 - Prob. 37SGCh. 1 - Prob. 38SGCh. 1 - Prob. 39SGCh. 1 - Prob. 40SGCh. 1 - Prob. 41SGCh. 1 - Prob. 42SGCh. 1 - Prob. 43SGCh. 1 - Prob. 44SGCh. 1 - Prob. 45SGCh. 1 - Prob. 46SGCh. 1 - Electronic components in computers process data...Ch. 1 - Prob. 2TFCh. 1 - Prob. 3TFCh. 1 - Prob. 4TFCh. 1 - Prob. 5TFCh. 1 - Prob. 6TFCh. 1 - Prob. 7TFCh. 1 - Prob. 8TFCh. 1 - Prob. 9TFCh. 1 - Prob. 10TFCh. 1 - Operating systems are a widely recognized example...Ch. 1 - Prob. 12TFCh. 1 - Prob. 1MCCh. 1 - Prob. 2MCCh. 1 - Prob. 3MCCh. 1 - Prob. 4MCCh. 1 - Prob. 5MCCh. 1 - Prob. 6MCCh. 1 - Prob. 7MCCh. 1 - Prob. 8MCCh. 1 - Prob. 1MCh. 1 - Prob. 2MCh. 1 - Prob. 3MCh. 1 - Prob. 4MCh. 1 - Prob. 5MCh. 1 - Prob. 6MCh. 1 - Prob. 7MCh. 1 - fileCh. 1 - Prob. 9MCh. 1 - Prob. 10MCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 13CTCh. 1 - Prob. 14CTCh. 1 - Prob. 15CTCh. 1 - Prob. 16CTCh. 1 - Prob. 17CTCh. 1 - Prob. 18CTCh. 1 - Prob. 19CTCh. 1 - Prob. 20CTCh. 1 - Prob. 21CTCh. 1 - Prob. 22CTCh. 1 - What are some popular programming languages?Ch. 1 - Prob. 24CTCh. 1 - Prob. 25CTCh. 1 - Prob. 26CTCh. 1 - Prob. 27CTCh. 1 - Prob. 1PSCh. 1 - Prob. 2PSCh. 1 - Prob. 3PSCh. 1 - Prob. 4PSCh. 1 - Prob. 5PSCh. 1 - Prob. 6PSCh. 1 - Prob. 7PSCh. 1 - Prob. 8PSCh. 1 - Prob. 9PSCh. 1 - Prob. 10PSCh. 1 - Prob. 11PSCh. 1 - Prob. 1.1ECh. 1 - Prob. 1.2ECh. 1 - Prob. 1.3ECh. 1 - Prob. 2.1ECh. 1 - Prob. 3.1ECh. 1 - Prob. 3.2ECh. 1 - Prob. 3.3ECh. 1 - Prob. 4.1ECh. 1 - Prob. 4.2ECh. 1 - Prob. 4.3ECh. 1 - Prob. 5.1ECh. 1 - Prob. 5.2ECh. 1 - Prob. 5.3ECh. 1 - Prob. 1IRCh. 1 - Prob. 2IRCh. 1 - Prob. 3IRCh. 1 - Prob. 4IRCh. 1 - Prob. 5IRCh. 1 - Prob. 1CTQCh. 1 - Prob. 2CTQCh. 1 - Prob. 3CTQCh. 1 - Prob. 4CTQ
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- #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Output: Exercise 1:====================Go Kean! Have a great semester! Go Kean! Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!arrow_forward(OnlineGDB) 1. Please read and run the following code and answer the questions.#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} What is the output of the program? Please explain why.arrow_forward1.[30 pts] Answer the following questions: a. [10 pts] Write a Boolean equation in sum-of-products canonical form for the truth table shown below: A B C Y 0 0 0 1 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 1 1 0 1 1 1 1 0 a. [10 pts] Minimize the Boolean equation you obtained in (a). b. [10 pts] Implement, using Logisim, the simplified logic circuit. Include an image of the circuitarrow_forward
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