Chapter 1, Problem 25P

Interpretation Introduction

(a)

Interpretation:

Convert the temperature from Celsius to Fahrenheit scale and Kelvin scale.

25° C.

Concept Introduction:

Temperature can be converted from Celsius scale to Fahrenheit scale using the following conversion factor.

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

Temperature can be converted from Celsius scale to Kelvin scale using the conversion factor.

$\text{K}{=}^0\text{C}+273$.

Answer to Problem 25P

The temperature in Kelvin = 298 K

The temperature in Fahrenheit n =77° F.

Explanation of Solution

Converting 25⁰ C to Fahrenheit:

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

$\begin{array}{l}{}^0\text{F}=\frac{9}{5}({25}^0)+32\\ ={77}^0\text{F}\end{array}$

Converting 25⁰ C to Kelvin:

$\text{K}{=}^0\text{C}+273$

$\begin{array}{r}\text{K}={25}^0\text{C}+273\\ =298\text{ K}\end{array}$.

Interpretation Introduction

(b)

Interpretation:

Convert the temperature from Celsius to Fahrenheit scale and Kelvin scale.

40° C.

Concept Introduction:

Temperature can be converted from Celsius scale to Fahrenheit scale using the following conversion factor.

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

Temperature can be converted from Celsius scale to Kelvin scale using the conversion factor.

$\text{K}{=}^0\text{C}+273$.

Answer to Problem 25P

The temperature in Kelvin = 313 K

The temperature in Fahrenheit n =104° F.

Explanation of Solution

Converting 40⁰ C to Fahrenheit:

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

$\begin{array}{l}{}^0\text{F}=\frac{9}{5}({40}^0)+32\\ ={104}^0\text{F}\end{array}$

Converting 40⁰ C to Kelvin:

$\text{K}{=}^0\text{C}+273$

$\begin{array}{l}\text{K}={40}^0\text{C}+273\\ =313\text{K}\end{array}$.

Interpretation Introduction

(c)

Interpretation:

Convert the temperature from Celsius to Fahrenheit scale and Kelvin scale.

250° C.

Concept Introduction:

Temperature can be converted from Celsius scale to Fahrenheit scale using the following conversion factor.

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

Temperature can be converted from Celsius scale to Kelvin scale using the conversion factor.

$\text{K}{=}^0\text{C}+273$.

Answer to Problem 25P

The temperature in Kelvin = 523 K

The temperature in Fahrenheit = 482° F.

Explanation of Solution

Converting 250⁰ C to Fahrenheit:

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

$\begin{array}{l}{}^0\text{F}=\frac{9}{5}({250}^0)+32\\ ={482}^0\text{F}\end{array}$

Converting 250⁰ C to Kelvin:

$\text{K}{=}^0\text{C}+273$

$\begin{array}{l}\text{K}={250}^0\text{C}+273\\ =523\text{K}\end{array}$.

Interpretation Introduction

(d)

Interpretation:

Convert the temperature from Celsius to Fahrenheit scale and Kelvin scale.

-273° C.

Concept Introduction:

Temperature can be converted from Celsius scale to Fahrenheit scale using the following conversion factor.

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

Temperature can be converted from Celsius scale to Kelvin scale using the conversion factor.

$\text{K}{=}^0\text{C}+273$.

Answer to Problem 25P

The temperature in Kelvin = 0 K

The temperature in Fahrenheit = -459.4° F.

Explanation of Solution

Converting -273⁰ C to Fahrenheit:

${}^0\text{F}={\frac{9}{5}}^0\text{C}+32$

$\begin{array}{l}{}^0\text{F}=\frac{9}{5}(-{273}^0)+32\\ =-{459.4}^0\text{F}\end{array}$

Converting -273⁰ C to Kelvin:

$\text{K}{=}^0\text{C}+273$

$\begin{array}{l}\text{K}=-{273}^0\text{C}+273\\ =0\text{K}\end{array}$.