Basic Engineering Circuit Analysis
11th Edition
ISBN: 9781118992661
Author: Irwin, J. David, NELMS, R. M., 1939-
Publisher: Wiley,
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
thumb_up100%
Chapter 1, Problem 23P
Element A in the diagram in Fig. PI .23 absorbs 30 W of power. Calculate
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The solution is with a pen and paper, without artificial intelligence.
Q5 For the network of Fig. 1.42; determine re, Avmid, Zi, Avsmid, and the low cutoff frequency.
Ans: 30.23 2; 0.983; 21.13 KS; 0.955; 193.16 Hz.
14V
+
Vs
1 ΚΩ
0.1 µF
Vi
120 ΚΩ
B-100
0.1 µF
o Vo
30 ΚΩ
32.2 ΚΩ
18.2 ΚΩ
Fig. 1.42 Circuit for Q5.
31
Q1) (a) State Biot-Savart's law
(b) The y- and z-axes, respectively, carry filamentary currents 10 A along ay
and 20 A along -az. Find H at (- 3, 4, 5).
Chapter 1 Solutions
Basic Engineering Circuit Analysis
Ch. 1 - If the current in an electric conductor is 2.4 A,...Ch. 1 - Determine the time interval required for a 12�A...Ch. 1 - A lightning bolt carrying 30,000 A lasts for 50...Ch. 1 - If a 12-V battery delivers 100 J in 5 s, find (a)...Ch. 1 - The current in a conductor is 1.5 A. How many...Ch. 1 - If 60 C of charge pass through an electric...Ch. 1 - Determine the number of coulombs of charge...Ch. 1 - Five coulombs of charge pass through the element...Ch. 1 - The current that enters an element is shown in...Ch. 1 - The charge entering the positive terminal of an...
Ch. 1 - The charge entering the positive terminal of an...Ch. 1 - Prob. 12PCh. 1 - The power absorbed by the BOX in Fig. Pl. 13 is...Ch. 1 - The power absorbed by the BOX in Fig. Pl. 14 is...Ch. 1 - The energy absorbed by the BOX in Fig. P1.15 is...Ch. 1 - The charge that enters the BOX in Fig. P1.16 is...Ch. 1 - The energy absorbed by the BOX in Fig. Pl. 17 is...Ch. 1 - The charge entering the upper terminal of the BOX...Ch. 1 - The energy absorbed by the BOX in Fig. Pl. 19 is...Ch. 1 - Determine the amount of power absorbed or supplied...Ch. 1 - Calculate the power absorbed by element A in Fig....Ch. 1 - Calculate the power supplied by element A in Fig....Ch. 1 - Element A in the diagram in Fig. PI .23 absorbs 30...Ch. 1 - Element B in the diagram in Fig. P1.24 supplies 60...Ch. 1 - Element B in the diagram in Fig. PI .25 supplies...Ch. 1 - Element B in the diagram in Fig. Pl.26 supplies 72...Ch. 1 - (a) In Fig. Pl.27 (a), P1=36W. Is element 2...Ch. 1 - Two elements are connected in series, as shown in...Ch. 1 - Element 2 in Fig. Pl.29 absorbed 32W. Find the...Ch. 1 - Choose Is such that the power absorbed by element...Ch. 1 - Find the power that is absorbed or supplied by the...Ch. 1 - Find the power that is absorbed or supplied by the...Ch. 1 - Compute the power that is absorbed or supplied by...Ch. 1 - Find the power that is absorbed or supplied by...Ch. 1 - Find Ix in the network in Fig. P1.35.Ch. 1 - Prob. 36PCh. 1 - Find the power absorbed or supplied by element 1...Ch. 1 - Find the power absorbed or supplied by element 3...Ch. 1 - Find the power absorbed or supplied by element 1...Ch. 1 - Find Vx in the network in Fig. P1.40 using...Ch. 1 - Find Ix in the circuit in Fig. P1.41 using...Ch. 1 - Is the source Vs in the network in Fig. P1.42...Ch. 1 - Find I0 in the network in Fig. P1.43 using...Ch. 1 - Calculate the power absorbed by each element in...Ch. 1 - Calculate the power absorbed by each element in...Ch. 1 - In the circuit in Fig. P1.46, element 1 absorbs 40...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Q5) a) State Ampere's circuit law. b) In a certain conducting region, H = yz(x² + y²)ax - y²xzay + 4x²y²a, A/m. (a) Determine J at (5, 2, -3) (b) Find the current passing through x = -1, 0 < y, z <2 (c) Show that V⚫H=0arrow_forwardFig. 1.43 Circuit for Q6- Q7 For the network of Fig. 1.44: a-Determine fH; and fHo b- Find fg and fr. c- Sketch the frequency response for the high-frequency region using a Bode plot and determine the cutoff frequency. Ans: 277.89 KHz; 2.73 MHz; 895.56 KHz; 107.47 MHz. 14V Cw=5pF Cbc-12 pF Cwo-8pF Che=40. pF 5.6kQ C-8pF 68kQ 0.47µF ww 0.82 kQ V₁ 0.47uF AN B=120 3.3kQ 10ΚΩ 1.2k0 =20µF Fig. 1.44 Circuit for Q7.arrow_forwardQ3) An infinite long filamentary wire carries a current of 2A in the +z direction. calculate: (a)B at (-3,4,7) (b) the flux through the square loop described by 25 16,0 Sz≤4, 0=90°.arrow_forward
- Q3) An infinitely long conductor is bent into an L shape as shown in Figure below. If a direct current of 5 A flows in the current, find the magnetic field intensity at (2, 2, 0). 5 A 5 Aarrow_forwardEx. 1° let Ĥ = -y (x²+y^³) ax + x (x²+y"`) ây":" H 5 find J M total current Passing through Z=oplane with the rectangular -\-2<<2arrow_forwardQ) Given the magnetic field vector potential: A= y² za, +2(x+1)y z ay- (x+1) z² az (A/m), find: (1)magnetic flux density B, (2)magnetic field intensity H, (3) current density J and (4) the current passing through surface y = 1,0≤x≤1, 0 ≤z≤1.arrow_forward
- Q9 For the network of Fig. 1.46: a- Determine gmo and gm. b- Find A, and Ay, in the mid-frequency range. c- Determine fH; and fHo Ans: 3.33 mS; 1.91 mS; -4.39; -4.27; 1.84 MHz; 3.68 MHz. + 1.5 kQ 20V 3220ΚΩ 1µF 68kQ AN CwF4pF Co=8 pF Cwo=6pF Cgs=12pF 53.9ΚΩ Cds=3pF 6.8µF o Vo Dss=10mA Vp=-6V 15.6 ΚΩ 2.2k =10µF Fiarrow_forwardQs For the network of Fig. 1.45: a- Determine fH, and fHo b- Find fp and fr c- Sketch the frequency response for the high-frequency region using a Bode plot and determine the cutoff frequency. Ans: 2.87 MHz, 185.78 MHz, 1.05 MHz, 105 MHz. 14V CWF8pF Cwo-10pF Cbc-20 pF Cbe=30pF 120 ΚΩ Co=12pF 1 ΚΩ B-100 0.1 µF Vs 0.1 HF Z; Vo www 30 kQ 2.2 ΚΩ € 8.2 kQ Fig. 1.45 Circuit for Carrow_forward5 A Q4) A thin ring of radius 5 cm is placed on plane z = 1 cm so that its center is at (0,0,1 cm). If the ring carries 50 mA along a^, find H at (0,0,a).arrow_forward
- Q6) Find the current density J for the magnetic field intensity vectors: (a) H = x²ya, + y²zay - 2xza, (b) H = p²zap + p³a + 3pz²az sin cos (c) H = a, 2 +2arrow_forwardQ2) Line x = 0, y=0,0arrow_forwardQ4) Given the magnetic vector potential: A = y²z ax-(x + 1)z² az A/m Find(a) the magnetic flux density; (b)the magnetic flux through a square loop described by 0≤x≤1, 0 ≤ y ≤1, z=2.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSON
Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Programmable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill Education
Electric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSON
Engineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,
Lesson 2 - Source Transformations, Part 2 (Engineering Circuits); Author: Math and Science;https://www.youtube.com/watch?v=7gno74RhVGQ;License: Standard Youtube License