Chapter 1, Problem 1RVS

To determine

The translation of the following phrase, “Twice the difference of a number and 11” choice the correct answer from the following options.

$\begin{array}{l}\text{A}\text{. }x=0.2\left(11\right)\\ \text{B}\text{. }\frac{2x}{11}\\ \text{C}\text{. }2x+2=11\\ \text{D}\text{. }2\left(11x+2\right)\\ \text{E}\text{. }11x=2\\ \text{F}\text{. }0.2x=11\\ \text{G}\text{. }11\left(2x-y\right)\\ \text{H}\text{. }2\left(x-11\right)\\ \text{I}\text{. }11+2x=2\\ \text{J}\text{. }2x+y=11\\ \text{K}\text{. }2\left(x-y\right)=11\\ \text{L}\text{. }11\left(x+2x\right)\\ \text{M}\text{. }2\left(x+y\right)=11\\ \text{N}\text{. }2+\frac{x}{11}\\ \text{O}\text{. }\frac{11}{xy}\end{array}$

Answer to Problem 1RVS

Solution:

The correct option for ‘Twice the difference of a number and 11’ is $\underset{\_}{\text{H}\text{. }2\left(x-11\right)}$.

Explanation of Solution

Given Information:

The phrase is ‘Twice the difference of a number and 11’.

The options are following,

$\begin{array}{l}\text{A}\text{. }x=0.2\left(11\right)\\ \text{B}\text{. }\frac{2x}{11}\\ \text{C}\text{. }2x+2=11\\ \text{D}\text{. }2\left(11x+2\right)\\ \text{E}\text{. }11x=2\\ \text{F}\text{. }0.2x=11\\ \text{G}\text{. }11\left(2x-y\right)\\ \text{H}\text{. }2\left(x-11\right)\\ \text{I}\text{. }11+2x=2\\ \text{J}\text{. }2x+y=11\\ \text{K}\text{. }2\left(x-y\right)=11\\ \text{L}\text{. }11\left(x+2x\right)\\ \text{M}\text{. }2\left(x+y\right)=11\\ \text{N}\text{. }2+\frac{x}{11}\\ \text{O}\text{. }\frac{11}{xy}\end{array}$

Consider the provided phrase, ‘Twice the difference of a number and 11’.

Consider the unknown number to be x. The difference of the number and 11 is,

$x-11$

Twice the difference of a number and 11 is equal to the expression $\left(x-11\right)$ is multiplied by 2,

$2\cdot \left(x-11\right)$

Hence, the correct option is $\text{H}\text{. }2\left(x-11\right)$.