Chapter 1, Problem 1MCCP

In Exercises 1-12, solve each equation.

$-5+3\left(x+5\right)=2\left(3x-4\right)$

To determine

To calculate: The solution of the equation $-5+3\left(x-5\right)=2\left(3x-4\right)$.

Answer to Problem 1MCCP

Solution:

The solution of the equation $-5+3\left(x-5\right)=2\left(3x-4\right)$ is $\underset{\_}{\left\{6\right\}}$.

Explanation of Solution

Given:

The equation is $-5+3\left(x+5\right)=2\left(3x-4\right)$.

Calculation:

Apply the distributive property in the equation,

$-5+3x+15=6x-8$

Collect the variable terms on one side of the equation and the constant terms on the other side of the equation,

$3x-6x=-8-15+5$

Simplify the equation as shown below,

$-3x=-18$

Divide both the sides of the above equation by $-3$ to get the value of x

$\begin{array}{c}\frac{-3x}{-3}=\frac{-18}{-3}\\ x=6\end{array}$

Hence, the solution of the equation $-5+3\left(x-5\right)=2\left(3x-4\right)$ is $\left\{6\right\}$.