Interpretation Introduction Interpretation: The given statement, “the properties of the substances around us depends on the atoms and molecules that compose them” is to be explained with the help of an example. Explanation Any change in the composition of a substance results in differences in the properties of the substance. For example: Oxygen molecules combines with hemoglobin present in the blood that supplies oxygen to all the cells and tissues of the body. But when carbon monoxide levels in the body rises than that of oxygen level, the carbon monoxide molecules in the same way combine with hemoglobin by preventing the binding of oxygen molecules to it. This implies that the shape and size of carbon monoxide molecules are similar to that of oxygen gas molecules. But when there is a change in the molecules of atoms like the addition of oxygen atom leads to a change in the properties of the carbon monoxide molecules because addition of one oxygen atom to carbon monoxide changes it to carbon dioxide i...

Chemistry: A Molecular Approach, Books a la Carte Edition; Modified MasteringChemistry with Pearson eText -- ValuePack Access Card -- for Chemistry: A Molecular Approach, 4/e

1st Edition

ISBN: 9780134465654

Author: Tro

Publisher: Pearson Education

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Chapter 1, Problem 1E

Interpretation Introduction

Interpretation: The given statement, “the properties of the substances around us depends on the atoms and molecules that compose them” is to be explained with the help of an example.

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Chapter 1 Solutions

Chemistry: A Molecular Approach, Books a la Carte Edition; Modified MasteringChemistry with Pearson eText -- ValuePack Access Card -- for Chemistry: A Molecular Approach, 4/e

Ch. 1 - A chemist mixes sodium with water and witnesses a...Ch. 1 - Q2. This image represents a particulate view of a...Ch. 1 - Which change is a physical change? a) Wood burning...Ch. 1 - Q4. Which property of rubbing alcohol is a...Ch. 1 - Convert 85F to K. a) 181.1 K b) 358 K c) 29.4 K d)...Ch. 1 - Express the quantity 33.2 10?4 m in mm. a) 33.2...Ch. 1 - Q7. What is the mass of a 1.75 L sample of a...Ch. 1 - Perform the calculation to the correct number of...Ch. 1 - Q9. Perform the calculation to the correct number...Ch. 1 - Q10. Convert 1285 cm2 to m2. a) 1.285 × 107...

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