Explanation Given: The radius of the sun is 7.0 × 10 5 k m , the average density of the sun is 1.4 × 10 3 k g/m 3 , and the diameter of the moon is 2.16 × 10 3 m i l e s . Convert the radius of the sun into meters as follows: r = 7.0 × 10 5 km ( 10 3 m 1 km ) = 7.0 × 10 8 cm Now, the volume of the sun is as follows: V = 4 3 π r 3 Substitute 3.14 for π and 7.0 × 10 10 cm for r : V = 4 3 ( 3.14 ) ( 7.0 × 10 8 m ) 3 = 1.436 × 10 27 m 3 Now, the mass of the sun is calculated as follows: m = ( d ) ( V ) Here, d is the density and V is the volume. Substitute 1.4 × 10 3 kg/m 3 for d and 1.436 × 10 27 m 3 for V : m = ( 1.4 × 10 3 kg/m 3 ) ( 1.436 × 10 27 m 3 ) = 2.01 × 10 30 kg Now, the black hole has a mass of 1 × 10 3 s u n s . So, the mass of the black hole is calculated as follows: m b = ( 2.01 × 10 30 kg ) ( 10 3 g 1 kg ) ( 1.0 × 10 3 ) = 2

Chemistry: A Molecular Approach, Books a la Carte Edition; Modified MasteringChemistry with Pearson eText -- ValuePack Access Card -- for Chemistry: A Molecular Approach, 4/e

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ISBN: 9780134465654

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Chapter 1, Problem 138E

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Interpretation: The density of the black hole in gram per cubic centimeters is to be determined.

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Chapter 1, Problem 137E

Chapter 1, Problem 139E

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Chemistry: A Molecular Approach, Books a la Carte Edition; Modified MasteringChemistry with Pearson eText -- ValuePack Access Card -- for Chemistry: A Molecular Approach, 4/e

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