From the given data, density of the pheromone should be determined. Concept Introduction: V o l u m e o f a c y l i n d e r = a r e a × h e i g h t = π r 2 h D e n s i t y = m a s s V o l u m e Conversion formula: 1 mile = 1609 metre 1 centimetre = 0 .01 metre 1 ft = 12 in 1 in = 2 .54 cm 1 cm 3 =1mL 1 L = 1000 m L

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Answer 1

Question

Chapter 1, Problem 1.99QP

Interpretation Introduction

Interpretation: From the given data, density of the pheromone should be determined.

Concept Introduction:

$Volume of a cylinder = area × height = π r2 h$

$Density= mass Volume$

Conversion formula:
$1 mile = 1609 metre1 centimetre = 0.01 metre$

$1 ft = 12 in1 in = 2.54 cm$

$1 cm3 =1mL1 L = 1000 m L$

Expert Solution & Answer

Answer to Problem 1.99QP

Answer

Density $= 4.0 ×10-19 g /L$

Explanation of Solution

Explanation

To determine: density of the pheromone s

To determine the density of the pheromone s, following steps should be followed,

To convert: The given radius and height from mile to centimeter and from foot to centimeter respectively.

$Radius =8.05 ×104 cmHeight= 1.22 × 103cm$

The given radius is $0.50 mi$ . The given radius can be converted in to centimeter by using the given conversion formula, that is,

$1 mile = 1609 metre1 centimetre = 0.01 metre$

$0.50 mi × 1609 m1 mi × 1 cm0.01 m = 8.05 ×104cm$

The given height in foot is $40 ft$ , the given height can be converted to centimeter by using the given formula;

$1 ft = 12 in1 in = 2.54 cm$

$40 ft × 12 in1 ft ×2.54 cm1in = 1.22 × 103 cm$

To determine the volume of a cylinder

$Volume = 2.48 ×1010 L$

Volume of cylinder can be determined by using the given formula. That is,

$Volume of a cylinder = area × height = π r2 h$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm3$

It is needed to convert the volume to litters by using the given conversion formula.

$1 cm3 =1mL1 L = 1000 m L$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm32.48 1013 cm3 ×1 mL1 cm3 × 1L1000 mL = 2.48 × 1010L$

To determine: Density of the pheromone

$4.0 × 10-19 g/L$

Density of the pheromone can be determined by using the given formula,

$Density= mass Volume$

Here,

$Mass= 1.0 × 10-8gVolume= 2.48 × 1010L Density =1.0 × 10-8g2.48 × 1010L = 4.0 × 10-19 g/L$

Conclusion

Conclusion

From the given data, density of the pheromone is determined.

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Answer 2

Question

Chapter 1, Problem 1.99QP

Interpretation Introduction

Interpretation: From the given data, density of the pheromone should be determined.

Concept Introduction:

$Volume of a cylinder = area × height = π r2 h$

$Density= mass Volume$

Conversion formula:
$1 mile = 1609 metre1 centimetre = 0.01 metre$

$1 ft = 12 in1 in = 2.54 cm$

$1 cm3 =1mL1 L = 1000 m L$

Expert Solution & Answer

Answer to Problem 1.99QP

Answer

Density $= 4.0 ×10-19 g /L$

Explanation of Solution

Explanation

To determine: density of the pheromone s

To determine the density of the pheromone s, following steps should be followed,

To convert: The given radius and height from mile to centimeter and from foot to centimeter respectively.

$Radius =8.05 ×104 cmHeight= 1.22 × 103cm$

The given radius is $0.50 mi$ . The given radius can be converted in to centimeter by using the given conversion formula, that is,

$1 mile = 1609 metre1 centimetre = 0.01 metre$

$0.50 mi × 1609 m1 mi × 1 cm0.01 m = 8.05 ×104cm$

The given height in foot is $40 ft$ , the given height can be converted to centimeter by using the given formula;

$1 ft = 12 in1 in = 2.54 cm$

$40 ft × 12 in1 ft ×2.54 cm1in = 1.22 × 103 cm$

To determine the volume of a cylinder

$Volume = 2.48 ×1010 L$

Volume of cylinder can be determined by using the given formula. That is,

$Volume of a cylinder = area × height = π r2 h$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm3$

It is needed to convert the volume to litters by using the given conversion formula.

$1 cm3 =1mL1 L = 1000 m L$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm32.48 1013 cm3 ×1 mL1 cm3 × 1L1000 mL = 2.48 × 1010L$

To determine: Density of the pheromone

$4.0 × 10-19 g/L$

Density of the pheromone can be determined by using the given formula,

$Density= mass Volume$

Here,

$Mass= 1.0 × 10-8gVolume= 2.48 × 1010L Density =1.0 × 10-8g2.48 × 1010L = 4.0 × 10-19 g/L$

Conclusion

Conclusion

From the given data, density of the pheromone is determined.

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Answer 3

Question

Chapter 1, Problem 1.99QP

Interpretation Introduction

Interpretation: From the given data, density of the pheromone should be determined.

Concept Introduction:

$Volume of a cylinder = area × height = π r2 h$

$Density= mass Volume$

Conversion formula:
$1 mile = 1609 metre1 centimetre = 0.01 metre$

$1 ft = 12 in1 in = 2.54 cm$

$1 cm3 =1mL1 L = 1000 m L$

Expert Solution & Answer

Answer to Problem 1.99QP

Answer

Density $= 4.0 ×10-19 g /L$

Explanation of Solution

Explanation

To determine: density of the pheromone s

To determine the density of the pheromone s, following steps should be followed,

To convert: The given radius and height from mile to centimeter and from foot to centimeter respectively.

$Radius =8.05 ×104 cmHeight= 1.22 × 103cm$

The given radius is $0.50 mi$ . The given radius can be converted in to centimeter by using the given conversion formula, that is,

$1 mile = 1609 metre1 centimetre = 0.01 metre$

$0.50 mi × 1609 m1 mi × 1 cm0.01 m = 8.05 ×104cm$

The given height in foot is $40 ft$ , the given height can be converted to centimeter by using the given formula;

$1 ft = 12 in1 in = 2.54 cm$

$40 ft × 12 in1 ft ×2.54 cm1in = 1.22 × 103 cm$

To determine the volume of a cylinder

$Volume = 2.48 ×1010 L$

Volume of cylinder can be determined by using the given formula. That is,

$Volume of a cylinder = area × height = π r2 h$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm3$

It is needed to convert the volume to litters by using the given conversion formula.

$1 cm3 =1mL1 L = 1000 m L$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm32.48 1013 cm3 ×1 mL1 cm3 × 1L1000 mL = 2.48 × 1010L$

To determine: Density of the pheromone

$4.0 × 10-19 g/L$

Density of the pheromone can be determined by using the given formula,

$Density= mass Volume$

Here,

$Mass= 1.0 × 10-8gVolume= 2.48 × 1010L Density =1.0 × 10-8g2.48 × 1010L = 4.0 × 10-19 g/L$

Conclusion

Conclusion

From the given data, density of the pheromone is determined.

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Answer 4

Question

Chapter 1, Problem 1.99QP

Interpretation Introduction

Interpretation: From the given data, density of the pheromone should be determined.

Concept Introduction:

$Volume of a cylinder = area × height = π r2 h$

$Density= mass Volume$

Conversion formula:
$1 mile = 1609 metre1 centimetre = 0.01 metre$

$1 ft = 12 in1 in = 2.54 cm$

$1 cm3 =1mL1 L = 1000 m L$

Expert Solution & Answer

Answer to Problem 1.99QP

Answer

Density $= 4.0 ×10-19 g /L$

Explanation of Solution

Explanation

To determine: density of the pheromone s

To determine the density of the pheromone s, following steps should be followed,

To convert: The given radius and height from mile to centimeter and from foot to centimeter respectively.

$Radius =8.05 ×104 cmHeight= 1.22 × 103cm$

The given radius is $0.50 mi$ . The given radius can be converted in to centimeter by using the given conversion formula, that is,

$1 mile = 1609 metre1 centimetre = 0.01 metre$

$0.50 mi × 1609 m1 mi × 1 cm0.01 m = 8.05 ×104cm$

The given height in foot is $40 ft$ , the given height can be converted to centimeter by using the given formula;

$1 ft = 12 in1 in = 2.54 cm$

$40 ft × 12 in1 ft ×2.54 cm1in = 1.22 × 103 cm$

To determine the volume of a cylinder

$Volume = 2.48 ×1010 L$

Volume of cylinder can be determined by using the given formula. That is,

$Volume of a cylinder = area × height = π r2 h$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm3$

It is needed to convert the volume to litters by using the given conversion formula.

$1 cm3 =1mL1 L = 1000 m L$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm32.48 1013 cm3 ×1 mL1 cm3 × 1L1000 mL = 2.48 × 1010L$

To determine: Density of the pheromone

$4.0 × 10-19 g/L$

Density of the pheromone can be determined by using the given formula,

$Density= mass Volume$

Here,

$Mass= 1.0 × 10-8gVolume= 2.48 × 1010L Density =1.0 × 10-8g2.48 × 1010L = 4.0 × 10-19 g/L$

Conclusion

Conclusion

From the given data, density of the pheromone is determined.

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Answer 5

Chapter 1, Problem 1.99QP

Interpretation Introduction

Interpretation: From the given data, density of the pheromone should be determined.

Concept Introduction:

$Volume of a cylinder = area × height = π r2 h$

$Density= mass Volume$

Conversion formula:
$1 mile = 1609 metre1 centimetre = 0.01 metre$

$1 ft = 12 in1 in = 2.54 cm$

$1 cm3 =1mL1 L = 1000 m L$

Expert Solution & Answer

Answer to Problem 1.99QP

Answer

Density $= 4.0 ×10-19 g /L$

Explanation of Solution

Explanation

To determine: density of the pheromone s

To determine the density of the pheromone s, following steps should be followed,

To convert: The given radius and height from mile to centimeter and from foot to centimeter respectively.

$Radius =8.05 ×104 cmHeight= 1.22 × 103cm$

The given radius is $0.50 mi$ . The given radius can be converted in to centimeter by using the given conversion formula, that is,

$1 mile = 1609 metre1 centimetre = 0.01 metre$

$0.50 mi × 1609 m1 mi × 1 cm0.01 m = 8.05 ×104cm$

The given height in foot is $40 ft$ , the given height can be converted to centimeter by using the given formula;

$1 ft = 12 in1 in = 2.54 cm$

$40 ft × 12 in1 ft ×2.54 cm1in = 1.22 × 103 cm$

To determine the volume of a cylinder

$Volume = 2.48 ×1010 L$

Volume of cylinder can be determined by using the given formula. That is,

$Volume of a cylinder = area × height = π r2 h$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm3$

It is needed to convert the volume to litters by using the given conversion formula.

$1 cm3 =1mL1 L = 1000 m L$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm32.48 1013 cm3 ×1 mL1 cm3 × 1L1000 mL = 2.48 × 1010L$

To determine: Density of the pheromone

$4.0 × 10-19 g/L$

Density of the pheromone can be determined by using the given formula,

$Density= mass Volume$

Here,

$Mass= 1.0 × 10-8gVolume= 2.48 × 1010L Density =1.0 × 10-8g2.48 × 1010L = 4.0 × 10-19 g/L$

Conclusion

Conclusion

From the given data, density of the pheromone is determined.

Answer 6

Chapter 1, Problem 1.99QP

Interpretation Introduction

Interpretation: From the given data, density of the pheromone should be determined.

Concept Introduction:

$Volume of a cylinder = area × height = π r2 h$

$Density= mass Volume$

Conversion formula:
$1 mile = 1609 metre1 centimetre = 0.01 metre$

$1 ft = 12 in1 in = 2.54 cm$

$1 cm3 =1mL1 L = 1000 m L$

Expert Solution & Answer

Answer to Problem 1.99QP

Answer

Density $= 4.0 ×10-19 g /L$

Explanation of Solution

Explanation

To determine: density of the pheromone s

To determine the density of the pheromone s, following steps should be followed,

To convert: The given radius and height from mile to centimeter and from foot to centimeter respectively.

$Radius =8.05 ×104 cmHeight= 1.22 × 103cm$

The given radius is $0.50 mi$ . The given radius can be converted in to centimeter by using the given conversion formula, that is,

$1 mile = 1609 metre1 centimetre = 0.01 metre$

$0.50 mi × 1609 m1 mi × 1 cm0.01 m = 8.05 ×104cm$

The given height in foot is $40 ft$ , the given height can be converted to centimeter by using the given formula;

$1 ft = 12 in1 in = 2.54 cm$

$40 ft × 12 in1 ft ×2.54 cm1in = 1.22 × 103 cm$

To determine the volume of a cylinder

$Volume = 2.48 ×1010 L$

Volume of cylinder can be determined by using the given formula. That is,

$Volume of a cylinder = area × height = π r2 h$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm3$

It is needed to convert the volume to litters by using the given conversion formula.

$1 cm3 =1mL1 L = 1000 m L$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm32.48 1013 cm3 ×1 mL1 cm3 × 1L1000 mL = 2.48 × 1010L$

To determine: Density of the pheromone

$4.0 × 10-19 g/L$

Density of the pheromone can be determined by using the given formula,

$Density= mass Volume$

Here,

$Mass= 1.0 × 10-8gVolume= 2.48 × 1010L Density =1.0 × 10-8g2.48 × 1010L = 4.0 × 10-19 g/L$

Conclusion

Conclusion

From the given data, density of the pheromone is determined.

Answer 7

Chapter 1, Problem 1.99QP

Interpretation Introduction

Interpretation: From the given data, density of the pheromone should be determined.

Concept Introduction:

$Volume of a cylinder = area × height = π r2 h$

$Density= mass Volume$

Conversion formula:
$1 mile = 1609 metre1 centimetre = 0.01 metre$

$1 ft = 12 in1 in = 2.54 cm$

$1 cm3 =1mL1 L = 1000 m L$

Answer 8

Expert Solution & Answer

Answer to Problem 1.99QP

Answer

Density $= 4.0 ×10-19 g /L$

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Explanation

To determine: density of the pheromone s

To determine the density of the pheromone s, following steps should be followed,

To convert: The given radius and height from mile to centimeter and from foot to centimeter respectively.

$Radius =8.05 ×104 cmHeight= 1.22 × 103cm$

The given radius is $0.50 mi$ . The given radius can be converted in to centimeter by using the given conversion formula, that is,

$1 mile = 1609 metre1 centimetre = 0.01 metre$

$0.50 mi × 1609 m1 mi × 1 cm0.01 m = 8.05 ×104cm$

The given height in foot is $40 ft$ , the given height can be converted to centimeter by using the given formula;

$1 ft = 12 in1 in = 2.54 cm$

$40 ft × 12 in1 ft ×2.54 cm1in = 1.22 × 103 cm$

To determine the volume of a cylinder

$Volume = 2.48 ×1010 L$

Volume of cylinder can be determined by using the given formula. That is,

$Volume of a cylinder = area × height = π r2 h$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm3$

It is needed to convert the volume to litters by using the given conversion formula.

$1 cm3 =1mL1 L = 1000 m L$

$Here,Radius (r) = 8.05 × 104 cmHeight (h) = 1.22 × 103 cmVolume of a cylinder = π r2hπ =3.14Volume of a cylinder =3.14×(8.05 × 104 cm)2 × (1.22 × 103 cm) = 2.48 1013 cm32.48 1013 cm3 ×1 mL1 cm3 × 1L1000 mL = 2.48 × 1010L$