Chapter 1, Problem 1.82QP

(a)

Interpretation Introduction

Interpretation:

The given number $\text{3}\text{.24}\text{×}{\text{10}}^{\text{3}}$ has to be expressed in standard notation.

Concept Introduction:

Standard notation:

It is the normal way of writing the numbers.  It differs from scientific notation as given below:

  $\begin{array}{l}\text{scientific}\text{notation}\text{=}\text{N}\text{×}{\text{10}}^{\text{a}}\\ \text{standard}\text{notation}\text{=}\text{N}\\ \text{Example:}\\ \text{standard}\text{value}\text{=}\text{1300000}\\ \text{scientific}\text{value}\text{=}\text{1}\text{.3}\text{×}{\text{10}}^{\text{6}}\end{array}$

Explanation of Solution

The given number is $\text{3}\text{.24}\text{×}{\text{10}}^{\text{3}}$.

To give the standard notation, the decimal point is removed.

  $\text{3}\text{.24}\text{×}{\text{10}}^{\text{3}}\text{=}\text{3240}$

(b)

Interpretation Introduction

Interpretation:

The given number $\text{1}\text{.50}\text{×}{\text{10}}^{\text{4}}$ has to be expressed in standard notation.

Concept Introduction:

Refer to part (a).

Explanation of Solution

The given number is $\text{1}\text{.50}\text{×}{\text{10}}^{\text{4}}$.

The standard notation of the given value is

  $\text{1}\text{.50}\text{×}{\text{10}}^{\text{4}}=15000$

(c)

Interpretation Introduction

Interpretation:

The given number $\text{4}\text{.579}\text{×}{\text{10}}^{\text{-1}}$ has to be expressed in standard notation.

Concept Introduction:

Refer to part (a).

Explanation of Solution

The given number is $\text{4}\text{.579}\text{×}{\text{10}}^{\text{-1}}$.

The standard notation of the given value is

  $\text{4}\text{.579}\text{×}{\text{10}}^{\text{-1}}\text{=}\text{0}\text{.4579}$

(d)

Interpretation Introduction

Interpretation:

The given number $\text{-6}\text{.83}\text{×}{\text{10}}^{\text{5}}$ has to be expressed in standard notation.

Concept Introduction:

Refer to part (a).

Explanation of Solution

The given number is $\text{-6}\text{.83}\text{×}{\text{10}}^{\text{5}}$.

The standard notation of the given value is

  $\text{-6}\text{.83}\text{×}{\text{10}}^{\text{5}}\text{=}\text{-683000}$

(e)

Interpretation Introduction

Interpretation:

The given number $\text{-8}\text{.21}\text{×}{\text{10}}^{\text{-2}}$ has to be expressed in standard notation.

Concept Introduction:

Refer to part (a).

Explanation of Solution

The given number is $\text{-8}\text{.21}\text{×}{\text{10}}^{\text{-2}}$.

The standard notation of the given value is

  $\text{-8}\text{.21}\text{×}{\text{10}}^{\text{-2}}\text{=}\text{-0}\text{.0821}$

(f)

Interpretation Introduction

Interpretation:

The given number $\text{2}\text{.9979}\text{×}{\text{10}}^{\text{8}}$ has to be expressed in standard notation.

Concept Introduction:

Refer to part (a).

Explanation of Solution

The given number is $\text{2}\text{.9979}\text{×}{\text{10}}^{\text{8}}$.

The standard notation of the given value is

  $\text{2}\text{.9979}\text{×}{\text{10}}^{\text{8}}\text{=}\text{299790000}$

(g)

Interpretation Introduction

Interpretation:

The given number $\text{1}\text{.50}\text{×}{\text{10}}^{\text{0}}$ has to be expressed in standard notation.

Concept Introduction:

Refer to part (a).

Explanation of Solution

The given number is $\text{1}\text{.50}\text{×}{\text{10}}^{\text{0}}$.

The standard notation of the given number is

  $\text{1}\text{.50}\text{×}{\text{10}}^{\text{0}}\text{=}\text{1}\text{.50}$

(h)

Interpretation Introduction

Interpretation:

The given number $\text{6}\text{.02}\text{×}{\text{10}}^{\text{23}}$ has to be expressed in standard notation.

Concept Introduction:

Refer to part (a).

Explanation of Solution

The given number is $\text{6}\text{.02}\text{×}{\text{10}}^{\text{23}}$.

The standard notation of the given number is same as the value is very high to be represented as a normal number.

  $\text{6}\text{.02}\text{×}{\text{10}}^{\text{23}}\text{=}\text{6}\text{.02}\text{×}{\text{10}}^{\text{23}}$