
Concept explainers
(a)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structures are not resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
The two structures have completely different carbon skeleton. The first one has a six membered ring while the second has a seven membered ring. Since these two structures do not have the same position of the atoms, they cannot be resonance structures.
From the position of atoms and electrons, it is found that the given pair is not resonance structures of one another.
(b)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
In these two structures, the position of the hydrogen atoms is not the same. Hence, these structures cannot be resonance structures of each other.
From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.
(c)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structure is resonance structures of one another.
Explanation of Solution
The structures of the given pair are as shown below.
To obtain the second resonance structure, two curved arrows are drawn and the electrons are moved accordingly. The two structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(d)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structure is resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
To obtain the second resonance structure, two curved arrows are drawn and the valence electrons are moved accordingly. Similarly, to arrive at the third resonance structure, two curved arrows are drawn and valence electrons are moved accordingly. The resonance structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(e)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structure is resonance structures of one another.
Explanation of Solution
The structures of the given pair are shown below:
To obtain the second resonance structure, a curved arrow is drawn and the valence electrons are moved accordingly. Similarly, to arrive at the third resonance structure, two curved arrows are drawn and valence electrons are moved accordingly. The resonance structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(f)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structure of the given pair is as follows:
Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is the same. Therefore, the given pair is not resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.
(g)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structure of the given pair is as follows:
Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is the same. Therefore, the given pair is not resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.
(h)
Interpretation:
It is to be determined if the given pair is not resonance structures of one another.
Concept introduction:
Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Answer to Problem 1.75P
The given structure is not resonance structures of one another.
Explanation of Solution
The structure of the given pair is as follows:
Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is different; at the same time, one H atom changes its position. Therefore, the given pair is not resonance structures of one another.
From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.
Want to see more full solutions like this?
Chapter 1 Solutions
Organic Chemistry: Principles And Mechanisms
- Absorbance and transmittance are related by: A = -log(T) A solution has a transmittance of 35% in a 1-cm-pathlength cell at a certain wavelength. Calculate the transmittance if you dilute 25.0 mL of the solution to 50.0 mL? (A = εbc) What is the transmittance of the original solution if the pathlength is increased to 10 cm?arrow_forwardUnder what conditions will Beer’s Law most likely NO LONGER be linear? When the absorbing species is very dilute. When the absorbing species participates in a concentration-dependent equilibrium. When the solution being studied contains a mixture of ions.arrow_forwardCompared to incident (exciting) radiation, fluorescence emission will have a: Higher energy Higher frequency Longer wavelengtharrow_forward
- Lin and Brown described a quantitative method for methanol based on its effect on the visible spectrum of methylene blue. In the absence of methanol, methylene blue has two prominent absorption bands at 610 nm and 663 nm, which correspond to the monomer and the dimer, respectively. In the presence of methanol, the intensity of the dimer’s absorption band decreases, while that for the monomer increases. For concentrations of methanol between 0 and 30% v/v, the ratio of the two absorbance, A663/ A610, is a linear function of the amount of methanol. Use the following standardization data to determine the %v/v methanol in a sample if A610 is 0.75 and A663 is 1.07.arrow_forwardThe crystal field splitting energy, Δ, of a complex is determined to be 2.9 × 10-19 What wavelength of light would this complex absorb? What color of light is this? What color would the compound be in solution?arrow_forwardA key component of a monochromator is the exit slit. As the exit slit is narrowed, the bandwidth of light (i.e., the range of wavelengths) exiting the slit gets smaller, leading to higher resolution. What is a possible disadvantage of narrowing the exit slit? (Hint: why might a narrower slit lower the sensitivity of the measurement?).arrow_forward
- An x-ray has a frequency of 3.33 × 1018 What is the wavelength of this light?arrow_forwardChoose the Lewis structure for the compound below: H2CCHOCH2CH(CH3)2 HH H :d H H H C. Η H H HH H H H H. H H H HH H H H H H- H H H C-H H H HHHHarrow_forwardEach of the highlighted carbon atoms is connected to hydrogen atoms.arrow_forward
- く Complete the reaction in the drawing area below by adding the major products to the right-hand side. If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area instead. Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center. More... No reaction. Explanation Check O + G 1. Na O Me Click and drag to start drawing a structure. 2. H + 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 000 Ar Parrow_forwardDraw a tetramer of this alternating copolymer.arrow_forwardH I T H HH H -H C. H- Identify and select all structures below that represent a constitutional isomer(s) of the compound shown above. H- H CIH H H H HHHH H H 0 ·H H– 冊 CH CHI HH C- H- H H- H H A. H H C H H- -H HH H B. H- -H D. H H H H • H -H E. -H H H HICH T HHH F. H-arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning

