Get Ready for Organic Chemistry
Get Ready for Organic Chemistry
2nd Edition
ISBN: 9780321774125
Author: KARTY, Joel
Publisher: PEARSON
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Chapter 1, Problem 1.75P
Interpretation Introduction

(a)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structures are not resonance structures of one another.

Explanation of Solution

The structures of the given pair are shown below:

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  1

The two structures have completely different carbon skeleton. The first one has a six membered ring while the second has a seven membered ring. Since these two structures do not have the same position of the atoms, they cannot be resonance structures.

Conclusion

From the position of atoms and electrons, it is found that the given pair is not resonance structures of one another.

Interpretation Introduction

(b)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structure is not resonance structures of one another.

Explanation of Solution

The structures of the given pair are shown below:

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  2

In these two structures, the position of the hydrogen atoms is not the same. Hence, these structures cannot be resonance structures of each other.

Conclusion

From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.

Interpretation Introduction

(c)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structure is resonance structures of one another.

Explanation of Solution

The structures of the given pair are as shown below.

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  3

To obtain the second resonance structure, two curved arrows are drawn and the electrons are moved accordingly. The two structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.

Conclusion

From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.

Interpretation Introduction

(d)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structure is resonance structures of one another.

Explanation of Solution

The structures of the given pair are shown below:

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  4

To obtain the second resonance structure, two curved arrows are drawn and the valence electrons are moved accordingly. Similarly, to arrive at the third resonance structure, two curved arrows are drawn and valence electrons are moved accordingly. The resonance structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.

Conclusion

From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.

Interpretation Introduction

(e)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structure is resonance structures of one another.

Explanation of Solution

The structures of the given pair are shown below:

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  5

To obtain the second resonance structure, a curved arrow is drawn and the valence electrons are moved accordingly. Similarly, to arrive at the third resonance structure, two curved arrows are drawn and valence electrons are moved accordingly. The resonance structures differ only in the placement of their electrons, not their atoms. Therefore, the given pair is resonance structures of one another.

Conclusion

From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.

Interpretation Introduction

(f)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structure is not resonance structures of one another.

Explanation of Solution

The structure of the given pair is as follows:

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  6

Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is the same. Therefore, the given pair is not resonance structures of one another.

Conclusion

From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.

Interpretation Introduction

(g)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structure is not resonance structures of one another.

Explanation of Solution

The structure of the given pair is as follows:

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  7

Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is the same. Therefore, the given pair is not resonance structures of one another.

Conclusion

From the position of atoms and valence electrons, it is found that the given pair is resonance structures of one another.

Interpretation Introduction

(h)

Interpretation:

It is to be determined if the given pair is not resonance structures of one another.

Concept introduction:

Resonance exists in species for which there are two or more valid Lewis structures. Resonance structures differ only in the placement of their electrons, not their atoms. Resonance stabilization is usually high when the resonance contributors are equivalent. More the number of the resonance contributors, the more is the resonance stabilization.

Expert Solution
Check Mark

Answer to Problem 1.75P

The given structure is not resonance structures of one another.

Explanation of Solution

The structure of the given pair is as follows:

Get Ready for Organic Chemistry, Chapter 1, Problem 1.75P , additional homework tip  8

Resonance structures differ only in the placement of their electrons, not their atoms. In the given pair, the placement of electrons is different; at the same time, one H atom changes its position. Therefore, the given pair is not resonance structures of one another.

Conclusion

From the position of atoms and valence electrons, it is found that the given pair is not resonance structures of one another.

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Chapter 1 Solutions

Get Ready for Organic Chemistry

Ch. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49PCh. 1 - Prob. 1.50PCh. 1 - Prob. 1.51PCh. 1 - Prob. 1.52PCh. 1 - Prob. 1.53PCh. 1 - Prob. 1.54PCh. 1 - Prob. 1.55PCh. 1 - Prob. 1.56PCh. 1 - Prob. 1.57PCh. 1 - Prob. 1.58PCh. 1 - Prob. 1.59PCh. 1 - Prob. 1.60PCh. 1 - Prob. 1.61PCh. 1 - Prob. 1.62PCh. 1 - Prob. 1.63PCh. 1 - Prob. 1.64PCh. 1 - Prob. 1.65PCh. 1 - Prob. 1.66PCh. 1 - Prob. 1.67PCh. 1 - Prob. 1.68PCh. 1 - Prob. 1.69PCh. 1 - Prob. 1.70PCh. 1 - Prob. 1.71PCh. 1 - Prob. 1.72PCh. 1 - Prob. 1.73PCh. 1 - Prob. 1.74PCh. 1 - Prob. 1.75PCh. 1 - Prob. 1.76PCh. 1 - Prob. 1.77PCh. 1 - Prob. 1.78PCh. 1 - Prob. 1.79PCh. 1 - Prob. 1.80PCh. 1 - Prob. 1.81PCh. 1 - Prob. 1.82PCh. 1 - Prob. 1.1YTCh. 1 - Prob. 1.2YTCh. 1 - Prob. 1.3YTCh. 1 - Prob. 1.4YTCh. 1 - Prob. 1.5YTCh. 1 - Prob. 1.6YTCh. 1 - Prob. 1.7YTCh. 1 - Prob. 1.8YTCh. 1 - Prob. 1.9YTCh. 1 - Prob. 1.10YTCh. 1 - Prob. 1.11YTCh. 1 - Prob. 1.12YTCh. 1 - Prob. 1.13YTCh. 1 - Prob. 1.14YTCh. 1 - Prob. 1.15YTCh. 1 - Prob. 1.16YTCh. 1 - Prob. 1.17YT
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