The summary of distribution of Antho1.

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Answer 1

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 1, Problem 165E

To determine

To explain: The summary of distribution of Antho1.

Expert Solution & Answer

Answer to Problem 165E

Solution: Antho1 is normally distributed with mean 1.630 and standard deviation 0.521.

Explanation of Solution

The provided output infers about the summary of Antho1 and its distribution. It says that the maximum 3.24 mg/100 gm and the minimum 0.207 mg/100 gm of Antho1 is present in blueberries. The central tendency measurements of the data, that is, median and mean, take the value of 1.620 and 1.630, respectively, which are close to each other. It indicates that the distribution is approximately symmetric. Moreover, the standard deviation of the data is provided as 0.521.

The provided histogram shows that the distribution curve is almost symmetric. The box plot shows that some points lie outside the range of the data. In normal quintile plot, the data points make a straight line except the outliers and that straight line clearly indicates that it follows the normal distribution.

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Answer 2

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 1, Problem 165E

To determine

To explain: The summary of distribution of Antho1.

Expert Solution & Answer

Answer to Problem 165E

Solution: Antho1 is normally distributed with mean 1.630 and standard deviation 0.521.

Explanation of Solution

The provided output infers about the summary of Antho1 and its distribution. It says that the maximum 3.24 mg/100 gm and the minimum 0.207 mg/100 gm of Antho1 is present in blueberries. The central tendency measurements of the data, that is, median and mean, take the value of 1.620 and 1.630, respectively, which are close to each other. It indicates that the distribution is approximately symmetric. Moreover, the standard deviation of the data is provided as 0.521.

The provided histogram shows that the distribution curve is almost symmetric. The box plot shows that some points lie outside the range of the data. In normal quintile plot, the data points make a straight line except the outliers and that straight line clearly indicates that it follows the normal distribution.

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Answer 3

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 1, Problem 165E

To determine

To explain: The summary of distribution of Antho1.

Expert Solution & Answer

Answer to Problem 165E

Solution: Antho1 is normally distributed with mean 1.630 and standard deviation 0.521.

Explanation of Solution

The provided output infers about the summary of Antho1 and its distribution. It says that the maximum 3.24 mg/100 gm and the minimum 0.207 mg/100 gm of Antho1 is present in blueberries. The central tendency measurements of the data, that is, median and mean, take the value of 1.620 and 1.630, respectively, which are close to each other. It indicates that the distribution is approximately symmetric. Moreover, the standard deviation of the data is provided as 0.521.

The provided histogram shows that the distribution curve is almost symmetric. The box plot shows that some points lie outside the range of the data. In normal quintile plot, the data points make a straight line except the outliers and that straight line clearly indicates that it follows the normal distribution.

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Answer 4

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 1, Problem 165E

To determine

To explain: The summary of distribution of Antho1.

Expert Solution & Answer

Answer to Problem 165E

Solution: Antho1 is normally distributed with mean 1.630 and standard deviation 0.521.

Explanation of Solution

The provided output infers about the summary of Antho1 and its distribution. It says that the maximum 3.24 mg/100 gm and the minimum 0.207 mg/100 gm of Antho1 is present in blueberries. The central tendency measurements of the data, that is, median and mean, take the value of 1.620 and 1.630, respectively, which are close to each other. It indicates that the distribution is approximately symmetric. Moreover, the standard deviation of the data is provided as 0.521.

The provided histogram shows that the distribution curve is almost symmetric. The box plot shows that some points lie outside the range of the data. In normal quintile plot, the data points make a straight line except the outliers and that straight line clearly indicates that it follows the normal distribution.

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Answer 5

Chapter 1, Problem 165E

To determine

To explain: The summary of distribution of Antho1.

Expert Solution & Answer

Answer to Problem 165E

Solution: Antho1 is normally distributed with mean 1.630 and standard deviation 0.521.

Explanation of Solution

The provided output infers about the summary of Antho1 and its distribution. It says that the maximum 3.24 mg/100 gm and the minimum 0.207 mg/100 gm of Antho1 is present in blueberries. The central tendency measurements of the data, that is, median and mean, take the value of 1.620 and 1.630, respectively, which are close to each other. It indicates that the distribution is approximately symmetric. Moreover, the standard deviation of the data is provided as 0.521.

The provided histogram shows that the distribution curve is almost symmetric. The box plot shows that some points lie outside the range of the data. In normal quintile plot, the data points make a straight line except the outliers and that straight line clearly indicates that it follows the normal distribution.

Answer 6

Chapter 1, Problem 165E

To determine

To explain: The summary of distribution of Antho1.

Expert Solution & Answer

Answer to Problem 165E

Solution: Antho1 is normally distributed with mean 1.630 and standard deviation 0.521.

Explanation of Solution

The provided output infers about the summary of Antho1 and its distribution. It says that the maximum 3.24 mg/100 gm and the minimum 0.207 mg/100 gm of Antho1 is present in blueberries. The central tendency measurements of the data, that is, median and mean, take the value of 1.620 and 1.630, respectively, which are close to each other. It indicates that the distribution is approximately symmetric. Moreover, the standard deviation of the data is provided as 0.521.

The provided histogram shows that the distribution curve is almost symmetric. The box plot shows that some points lie outside the range of the data. In normal quintile plot, the data points make a straight line except the outliers and that straight line clearly indicates that it follows the normal distribution.

Answer 7

Chapter 1, Problem 165E

To determine

To explain: The summary of distribution of Antho1.

Answer 8

Expert Solution & Answer

Answer to Problem 165E

Solution: Antho1 is normally distributed with mean 1.630 and standard deviation 0.521.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

The provided output infers about the summary of Antho1 and its distribution. It says that the maximum 3.24 mg/100 gm and the minimum 0.207 mg/100 gm of Antho1 is present in blueberries. The central tendency measurements of the data, that is, median and mean, take the value of 1.620 and 1.630, respectively, which are close to each other. It indicates that the distribution is approximately symmetric. Moreover, the standard deviation of the data is provided as 0.521.

The provided histogram shows that the distribution curve is almost symmetric. The box plot shows that some points lie outside the range of the data. In normal quintile plot, the data points make a straight line except the outliers and that straight line clearly indicates that it follows the normal distribution.

Answer 12

Ch. 1.1 - Prob. 1UYK Ch. 1.1 - Prob. 2UYK Ch. 1.1 - Prob. 3UYK Ch. 1.1 - Prob. 4UYK Ch. 1.1 - Prob. 5UYK Ch. 1.1 - Prob. 6UYK Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

The summary of distribution of Antho1.

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To explain: The summary of distribution of Antho1.

Answer to Problem 165E

Explanation of Solution

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