The data in the following table represent measurements of the masses and dimensions of solid cylinders of aluminum, copper, brass, tin, and iron. (a) Use these data to calculate the densities of these substances. (b) State how your results compare with those given in Table 14.1.
(a)
The densities of each substance.
Answer to Problem 1.61AP
The density of aluminum solid cylinders is
Explanation of Solution
Given info: The mass, diameter and length of each substance are given below,
Substance | Mass
| Diameter
| Length
|
Aluminum |
|
|
|
Copper |
|
|
|
Brass |
|
|
|
Tin |
|
|
|
Iron |
|
|
|
Formula to calculate the density of substance is,
Here,
Write the expression for the volume of solid cylinder,
Here,
Substitute
For aluminum:
Substitute
Thus, the density of aluminum solid cylinders is
For copper:
Substitute
Thus, the density of copper solid cylinders is
For brass:
Substitute
Thus, the density of brass solid cylinders is
For tin:
Substitute
Thus, the density of tin solid cylinders is
For iron:
Substitute
Thus, the density of iron solid cylinders is
Conclusion:
Therefore, the density of aluminum solid cylinders is
(b)
The comparison between results of part (a) and table
Answer to Problem 1.61AP
The density of aluminum from table is
Explanation of Solution
Given info:
Formula to calculate the percentage error is,
Here,
For aluminum:
From part (a), the density of the aluminum is
Substitute
Thus, the density of aluminum from table is
For copper:
From part (a), the density of the copper is
Substitute
Thus, the density of copper from table is
For brass:
From part (a), the density of the brass is
Substitute
Thus, the density of brass from table is
For tin:
From part (a), the density of the tin is
Substitute
Thus, the density of tin from table is
For iron:
From part (a), the density of the iron is
Substitute
Thus, the density of iron from table is
Conclusion:
Therefore, the density of aluminum from table is
Want to see more full solutions like this?
Chapter 1 Solutions
Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term
Additional Science Textbook Solutions
College Physics: A Strategic Approach (3rd Edition)
Loose Leaf For Integrated Principles Of Zoology
Chemistry & Chemical Reactivity
Biology: Life on Earth (11th Edition)
Fundamentals Of Thermodynamics
Fundamentals of Anatomy & Physiology (11th Edition)
- air is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cmarrow_forwardNo chatgpt pls will upvotearrow_forward13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forward
- No chatgpt pls will upvotearrow_forwarda cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forwardCalculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forward
- How can i solve this if n1 (refractive index of gas) and n2 (refractive index of plastic) is not known. And the brewsters angle isn't knownarrow_forward2. Consider the situation described in problem 1 where light emerges horizontally from ground level. Take k = 0.0020 m' and no = 1.0001 and find at which horizontal distance, x, the ray reaches a height of y = 1.5 m.arrow_forward2-3. Consider the situation of the reflection of a pulse at the interface of two string described in the previous problem. In addition to the net disturbances being equal at the junction, the slope of the net disturbances must also be equal at the junction at all times. Given that p1 = 4.0 g/m, H2 = 9.0 g/m and Aj = 0.50 cm find 2. A, (Answer: -0.10 cm) and 3. Ay. (Answer: 0.40 cm)please I need to show all work step by step problems 2 and 3arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON