Bundle: Automotive Technology: A Systems Approach, 6th + LMS Integrated for MindTap Auto Trades Printed Access Card
6th Edition
ISBN: 9781305366749
Author: Jack Erjavec, Rob Thompson
Publisher: Cengage Learning
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Chapter 1, Problem 15RQ
To be successful, todays automotive technician must have
- an understanding of electronics
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Students have asked these similar questions
For the walking-beam mechanism shown in Figure 3, find and plot the x and y coordinates of the
position of the coupler point P for one complete revolution of the crank O2A. Use the coordinate
system shown in Figure 3. Hint: Calculate them first with respect to the ground link 0204 and
then transform them into the global XY coordinate system.
y
-1.75
Ꮎ
Ꮎ
4
= 2.33
0242.22
L4
x
AP = 3.06
L2 = 1.0
W2
31°
B
03 L3 = 2.06
P
1
8
5
.06
6
7
P'
The link lengths, gear ratio (2), phase angle (Ø), and the value of 02 for some geared five bar
linkages are defined in Table 2. The linkage configuration and terminology are shown in Figure
2. For the rows assigned, find all possible solutions for angles 03 and 04 by the vector loop
method. Show your work in details: vector loop, vector equations, solution procedure.
Table 2
Row
Link 1 Link 2
Link 3
Link 4
Link 5
λ
Φ
Ө
a
6
1
7
9
4
2
30°
60°
P
y 4
YA
B
b
R4
R3
YA
A
Gear ratio:
a
02
d
05
r5
R5
R2
Phase angle: = 0₂-202
R1
05
02
r2
Figure 2.
04
X
Problem 4
A .025 lb bullet C is fired at end B of the 15-lb slender bar AB. The
bar is initially at rest, and the initial velocity of the bullet is 1500 ft/s
as shown. Assuming that the bullet becomes embedded in the bar,
find (a) the angular velocity @2 of the bar immediately after impact,
and (b) the percentage loss of kinetic energy as a result of the impact.
(c) After the impact, does the bar swing up 90° and reach the
horizontal? If it does, what is its angular velocity at this point?
Answers: (a). @2=1.6 rad/s; (b). 99.6% loss
=
(c). Ah2 0.212 ft. The bar does not reach horizontal.
y
X
4 ft
15 lb
V₁
1500 ft/s
0.025 lb
C
30°7
B
A
Chapter 1 Solutions
Bundle: Automotive Technology: A Systems Approach, 6th + LMS Integrated for MindTap Auto Trades Printed Access Card
Ch. 1 - Prob. 1RQCh. 1 - Explain the basic requirements for becoming a...Ch. 1 - List at least five different types of businesses...Ch. 1 - Name the different ways that you can gain work...Ch. 1 - Explain the implied difference between someone who...Ch. 1 - Individuals often begin a career as an automotive...Ch. 1 - Prob. 7RQCh. 1 - Prob. 8RQCh. 1 - Which of the following is typically included in a...Ch. 1 - Prob. 10RQ
Ch. 1 - Repair work performed on vehicles still under tire...Ch. 1 - Prob. 12RQCh. 1 - Normally, whose job is it to greet the customer...Ch. 1 - Technician A says that all an individual needs to...Ch. 1 - To be successful, todays automotive technician...Ch. 1 - A technician must have a minimum of year(s) of...Ch. 1 - An experienced technician who passes all eight...Ch. 1 - Technician A says battery warranties are often...Ch. 1 - Prob. 19RQCh. 1 - Ongoing technical training and support is...
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- The link lengths and the value of 2 and offset for some fourbar crank-slide linkages are defined in Table 1. The linkage configuration and terminology are shown in Figure 1. For the rows assigned, find (a) all possible solutions for angle & and slider position d by vector loop method. (b) the transmission angle corresponding to angle 03. (Hint: Treat the vector R4 as virtual rocker) Show your work in details: vector loop, vector equations, solution procedure. Table 1 Row Link 2 Link 3 Offset Ө a 1.4 4 1 45° b 3 8 2 -30° C 5 20 -5 225° 03 slider axis B X offset Link 2 A R3 Link 3 R4 04 R2 02 R1 d Figure 1. Xarrow_forward4. Two links made of heat treated 6061 aluminum (Sy = 276 MPa, Sys = 160 MPa) are pinned together using a steel dowel pin (Sy = 1398 MPa, Sys = 806 MPa) as shown below. The links are to support a load P with a factor of safety of at least 2.0. Determine if the link will fail first by tearout, direct shear of the pin, bearing stress on the link, or tensile stress at section AA. (Hint: find the load P for each case and choose the case that gives the smallest load.) P 8 mm P 8 mm ¡+A 3 mm →A 10 mm Parrow_forward1. For a feature other than a sphere, circularity is where: A. The axis is a straight line B. The modifier is specified with a size dimension C. All points of the surface intersected by any plane perpendicular to an axis or spine (curved line) are equidistant from that axis or spine D. All points of the surface intersected by any plane passing through a common center are equidistant from that center 2. What type of variation is limited by a circularity toler- ance zone? A. Ovality B. Tapering C. Bending D. Warping 3. How does the Rule #1 boundary affect the application of a circularity tolerance? A. The modifier must be used. B. The feature control frame must be placed next to the size dimension. C. The circularity tolerance value must be less than the limits of size tolerance. D. Circularity cannot be applied where a Rule #1 boundary exists. 4. A circularity tolerance may use a modifier. A. Ø B. F C. M D. ℗ 5. A real-world application for a circularity tolerance is: A. Assembly (i.e.,…arrow_forward
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