FUND OF ENG THERMODYN(LLF)+WILEYPLUS
FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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Chapter 1, Problem 1.4P

a.

To determine

Convert 1 L to in3 .

b.

To determine

Convert 650 J to Btu .

c.

To determine

Convert 0.135 kW to ft.lbf/s .

d.

To determine

Convert 378 g/s to lb/min

e.

To determine

Convert 304 kPa to lbf/in2 .

f.

To determine

Convert 55 m3/h to ft3/s .

g.

To determine

Convert 50 km/h to ft/s .

h.

To determine

Convert 8896 N to ton .

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Correct answers are written below. Detailed and correct solution only with fbd. I will upvote. 1: A 3 m alloy shaft fixed at one end has a torsional shearing stress capacity of 55 MPa. Due to improper fabrication, its cross-sectionalarea has become irregularly shaped. Its effective polar moment of inertia has become 2 x10-7 m4, and the maximum torque stress acts at 7.5 cm fromthe center of the shaft.[1]: If the shaft is to be replaced by a properly manufactured solid circular shaft that has a maximumshearing stress capacity of 70 MN/m2, what is the minimum diameter required so it can withstand the sameload? [2]: Calculate the thickness of a hollow circular shaft with the same outside diameter calculated initem [1] that can carry the same load. Limit the maximum shearing stress of the hollow circular shaft to0.09 GPa.Determine the angle of twist on the free end of the shaft. Use G = 150 x103 GPa. [3]: Use the solidcircular shaft from [1] and use the hollow circular shaft from [2].…
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Correct answers are written below. Detailed and correct solution only with fbd. I will upvote. 1: A 3 m alloy shaft fixed at one end has a torsional shearing stress capacity of 55 MPa. Due to improper fabrication, its cross-sectionalarea has become irregularly shaped. Its effective polar moment of inertia has become 2 x10-7 m4, and the maximum torque stress acts at 7.5 cm fromthe center of the shaft.[1]: If the shaft is to be replaced by a properly manufactured solid circular shaft that has a maximumshearing stress capacity of 70 MN/m2, what is the minimum diameter required so it can withstand the sameload? [2]: Calculate the thickness of a hollow circular shaft with the same outside diameter calculated initem [1] that can carry the same load. Limit the maximum shearing stress of the hollow circular shaft to0.09 GPa.Determine the angle of twist on the free end of the shaft. Use G = 150 x103 GPa. [3]: Use the solidcircular shaft from [1] and use the hollow circular shaft from [2].…

Chapter 1 Solutions

FUND OF ENG THERMODYN(LLF)+WILEYPLUS

Ch. 1 - Prob. 1.12ECh. 1 - Prob. 1.13ECh. 1 - Prob. 1.14ECh. 1 - Prob. 1.1CUCh. 1 - Prob. 1.2CUCh. 1 - Prob. 1.3CUCh. 1 - Prob. 1.4CUCh. 1 - Prob. 1.5CUCh. 1 - Prob. 1.6CUCh. 1 - Prob. 1.7CUCh. 1 - Prob. 1.8CUCh. 1 - Prob. 1.9CUCh. 1 - Prob. 1.10CUCh. 1 - Prob. 1.11CUCh. 1 - Prob. 1.12CUCh. 1 - Prob. 1.13CUCh. 1 - Prob. 1.14CUCh. 1 - Prob. 1.15CUCh. 1 - Prob. 1.16CUCh. 1 - Prob. 1.17CUCh. 1 - Prob. 1.18CUCh. 1 - Prob. 1.19CUCh. 1 - Prob. 1.20CUCh. 1 - Prob. 1.21CUCh. 1 - Prob. 1.22CUCh. 1 - Prob. 1.23CUCh. 1 - Prob. 1.24CUCh. 1 - Prob. 1.25CUCh. 1 - Prob. 1.26CUCh. 1 - Prob. 1.27CUCh. 1 - Prob. 1.28CUCh. 1 - Prob. 1.29CUCh. 1 - Prob. 1.30CUCh. 1 - Prob. 1.31CUCh. 1 - Prob. 1.32CUCh. 1 - Prob. 1.33CUCh. 1 - Prob. 1.34CUCh. 1 - Prob. 1.35CUCh. 1 - Prob. 1.36CUCh. 1 - Prob. 1.37CUCh. 1 - Prob. 1.38CUCh. 1 - Prob. 1.39CUCh. 1 - Prob. 1.40CUCh. 1 - Prob. 1.41CUCh. 1 - Prob. 1.42CUCh. 1 - Prob. 1.43CUCh. 1 - Prob. 1.44CUCh. 1 - Prob. 1.45CUCh. 1 - Prob. 1.46CUCh. 1 - Prob. 1.47CUCh. 1 - Prob. 1.48CUCh. 1 - Prob. 1.49CUCh. 1 - Prob. 1.50CUCh. 1 - Prob. 1.51CUCh. 1 - Prob. 1.52CUCh. 1 - Prob. 1.53CUCh. 1 - Prob. 1.54CUCh. 1 - Prob. 1.55CUCh. 1 - Prob. 1.56CUCh. 1 - Prob. 1.57CUCh. 1 - Prob. 1.58CUCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10PCh. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49P
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