
Concept explainers
(a)
Interpretation:
Whether silicon is more abundant or less abundant than aluminium in Earth’s crust has to be indicated.
Concept Introduction:
Element is a pure substance and it cannot be broken down into simpler pure substance by chemical means like
Elements that are laboratory synthesized are radioactive in nature and they convert back into the original naturally occurring element by emission of radiation. All the elements that occur naturally are not evenly distributed on earth and universe.
Radiations that are emitted from stars can be used to estimate the elemental composition of universe. This indicates that hydrogen and helium are mostly dominant. On Earth’s crust oxygen and silicon are the two elements that account for about
(b)
Interpretation:
Whether calcium is more abundant or less abundant than hydrogen in Earth’s crust has to be indicated.
Concept Introduction:
Element is a pure substance and it cannot be broken down into simpler pure substance by chemical means like chemical reaction, electric current, heat, or light. Over several centuries, the discovery of 118 known elements and its isolation have taken place. These 118 elements are the building blocks of all matter. Out of the 118 elements, eighty-eight elements are naturally occurring and the other 30 elements are laboratory synthesized by bombarding elements that naturally occur with small particles.
Elements that are laboratory synthesized are radioactive in nature and they convert back into the original naturally occurring element by emission of radiation. All the elements that occur naturally are not evenly distributed on earth and universe.
Radiations that are emitted from stars can be used to estimate the elemental composition of universe. This indicates that hydrogen and helium are mostly dominant. On Earth’s crust oxygen and silicon are the two elements that account for about
(c)
Interpretation:
Whether iron is more abundant or less abundant than oxygen in Earth’s crust has to be indicated.
Concept Introduction:
Element is a pure substance and it cannot be broken down into simpler pure substance by chemical means like chemical reaction, electric current, heat, or light. Over several centuries, the discovery of 118 known elements and its isolation have taken place. These 118 elements are the building blocks of all matter. Out of the 118 elements, eighty-eight elements are naturally occurring and the other 30 elements are laboratory synthesized by bombarding elements that naturally occur with small particles.
Elements that are laboratory synthesized are radioactive in nature and they convert back into the original naturally occurring element by emission of radiation. All the elements that occur naturally are not evenly distributed on earth and universe.
Radiations that are emitted from stars can be used to estimate the elemental composition of universe. This indicates that hydrogen and helium are mostly dominant. On Earth’s crust oxygen and silicon are the two elements that account for about
(d)
Interpretation:
Whether sodium is more abundant or less abundant than potassium in Earth’s crust has to be indicated.
Concept Introduction:
Element is a pure substance and it cannot be broken down into simpler pure substance by chemical means like chemical reaction, electric current, heat, or light. Over several centuries, the discovery of 118 known elements and its isolation have taken place. These 118 elements are the building blocks of all matter. Out of the 118 elements, eighty-eight elements are naturally occurring and the other 30 elements are laboratory synthesized by bombarding elements that naturally occur with small particles.
Elements that are laboratory synthesized are radioactive in nature and they convert back into the original naturally occurring element by emission of radiation. All the elements that occur naturally are not evenly distributed on earth and universe.
Radiations that are emitted from stars can be used to estimate the elemental composition of universe. This indicates that hydrogen and helium are mostly dominant. On Earth’s crust oxygen and silicon are the two elements that account for about

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Chapter 1 Solutions
General, Organic, And Biological Chemistry, Hybrid (with Owlv2 Quick Prep For General Chemistry Printed Access Card)
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- Can I please get the graph 1: Concentration vs. Density?arrow_forwardOrder the following series of compounds from highest to lowest reactivity to electrophilic aromatic substitution, explaining your answer: 2-nitrophenol, p-Toluidine, N-(4-methylphenyl)acetamide, 4-methylbenzonitrile, 4-(trifluoromethyl)benzonitrile.arrow_forwardOrdene la siguiente serie de compuestos de mayor a menor reactividad a la sustitución aromática electrofílica, explicando su respuesta: ácido bencenosulfónico, fluorobenceno, etilbenceno, clorobenceno, terc-butilbenceno, acetofenona.arrow_forward
- Can I please get all final concentrations please!arrow_forwardState the detailed mechanism of the reaction of benzene with isopropanol in sulfuric acid.arrow_forwardDo not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forward
- A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
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