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(a)
Interpretation:
Lewis structure for the given molecule is to be completed.
Concept introduction:
Lewis structures involve only valence electrons. When drawing a Lewis structure, the first step is to calculate the total number of valence electrons. For a complete Lewis structure of a molecule, the atoms must complete their normal valency by bond formation and lone pairs of electrons. Maximum number of covalent bonds formed by any neutral atom with maximum number of lone pairs is
| Atom | Number of bond | Number of lone pairs |
| C | 4 | 0 |
| H | 1 | 0 |
| O | 2 | 2 |
| N | 1 | 1 |
| F | 1 | 3 |
Answer to Problem 1.46P
The complete Lewis structure for the given molecule is
Explanation of Solution
The given structure is
Total valence electron count for the given molecule is
The other oxygen atom has formed only one bond with carbon. This is converted to a double bond and two lone pairs are placed on the oxygen atom so that its octet is complete. A double bond is placed between C and N atom to complete the octet of carbon and a lone pair is placed in nitrogen to complete its octet.
A triple bond is placed between the other C and N to complete the octet of carbon and a lone pair is placed in the nitrogen to complete its octet.
This structure now accounts for all 54 electrons and the octet of each atom, except hydrogen, is complete. The duet for all hydrogens is complete.
The Lewis structure for the given molecule is completed from total valence electron count.
(b)
Interpretation:
Lewis structure for the given molecule is to be completed.
Concept introduction:
Lewis structures involve only valence electrons. When drawing a Lewis structure, the first step is to calculate the total number of valence electrons. For a complete Lewis structure of a molecule, every carbon atom must form four covalent bonds whereas the hydrogen atom forms one bond.
Answer to Problem 1.46P
The complete Lewis structure for the given molecule is
Explanation of Solution
The given structure is
Total valence electron count for the given molecule must be
This structure now accounts for all 38 electrons and the octet of each atom, except hydrogen, is complete. The duet for all hydrogen atoms is complete.
The Lewis structure for the given molecule is completed from total valence electron count.
(c)
Interpretation:
Lewis structure for the given molecule is to be completed.
Concept introduction:
Lewis structures involve only valence electrons. When drawing a Lewis structure, the first step is to calculate the total number of valence electrons. For a complete Lewis structure of a molecule, the atoms must complete their normal valency by bond formation and lone pairs of electrons. Maximum numbers of covalent bonds formed by any neutral atom with maximum number of lone pair are
| Atom | Number of bond | Number of lone pairs |
| C | 4 | 0 |
| H | 1 | 0 |
| O | 2 | 2 |
| N | 1 | 1 |
Answer to Problem 1.46P
The complete Lewis structure for the given molecule is
Explanation of Solution
The given structure is
Total valence electron count for the given molecule is
The oxygen atom has formed only one bond with nitrogen. This is converted to a double bond and two lone pairs are placed on the oxygen atom so that its octet is complete. Another lone pair is placed on the nitrogen atom so that its octet is complete.
A double bond is placed between the C atoms attached to one hydrogen each. This completes the octet of both carbon atoms
This structure now accounts for all the 28 electrons, and the octet of each atom, except hydrogen, is complete. The duet for all hydrogen atoms is complete.
The Lewis structure for the given molecule is completed from total valence electron count.
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Chapter 1 Solutions
Organic Chemistry: Principles And Mechanisms: Study Guide/solutions Manual (second)
- Why is analysing salt content (using Mohr titration) in both regular & salt reduced tomato sauce important?arrow_forwardIn the image below, correctly name the glassware # _P ( Blank 1) and T ( Blank 2). 景 A W Blank # 1 Blank #2 1000 +19 E E D 0 0-0 G H A A K Π 12 R M N S 0-0-arrow_forwardFeedback: Your answer is incorrect. Predict the major products of the following organic reaction: CN Δ + A ? NC Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. esc Check 80 MH F1 F2 F3 F4 F5 50 @ # C % 95 € Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C A DII F6 F7 F8 7 * 8 Λ & 6 F9 F10 9 0 4arrow_forward
- Incorrect Feedback: Your answer is incorrect. Predict the major products of the following organic reaction: ཤིགས་བྱ རྩ་ཅད་ཀྱིས་༢༩ + Some important notes: A ^ ? • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. E Check 0 لا Save For La ©2025 McGraw Hill LLC. All Rights Reserved. Terms of All F9 Aarrow_forwardPredict the major products of the following organic reaction: + Δ A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privaarrow_forwardesc 2 Incorrect Feedback: Your answer is incorrect. Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? A O • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. . If your answer is no, check the box under the drawing area instead. Check F1 ! @ X C Save For Later Submit Assignment 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 80 et A ད 1 4 F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 # $ 45 % A 6 87 & * 8 9 ) 0 + ||arrow_forward
- Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ?A Δ O • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilit ku F11arrow_forward१ eq ine teaching and × + rn/takeAssignment/takeCovalentActivity.do?locator-assignment-take [Review Topics] [References] Write an acceptable IUPAC name for the compound below. (Only systematic names, not common names are accepted by this question.) Keep the information page open for feedback reference. The IUPAC name is In progress mit Answer Retry Entire Group 5 more group attempts remaining Cengage Learning | Cengage Technical Support Save and Exitarrow_forwardDraw the molecules.arrow_forward
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