Fundamentals Of Engineering Thermodynamics
9th Edition
ISBN: 9781119391388
Author: MORAN, Michael J., SHAPIRO, Howard N., Boettner, Daisie D., Bailey, Margaret B.
Publisher: Wiley,
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Chapter 1, Problem 1.41P
To determine
Reading of pressure gauge.
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Chapter 1 Solutions
Fundamentals Of Engineering Thermodynamics
Ch. 1 - Prob. 1.2ECh. 1 - Prob. 1.3ECh. 1 - Prob. 1.4ECh. 1 - Prob. 1.5ECh. 1 - Prob. 1.6ECh. 1 - Prob. 1.7ECh. 1 - Prob. 1.8ECh. 1 - Prob. 1.9ECh. 1 - Prob. 1.10ECh. 1 - Prob. 1.11E
Ch. 1 - Prob. 1.12ECh. 1 - Prob. 1.13ECh. 1 - Prob. 1.14ECh. 1 - Prob. 1.1CUCh. 1 - Prob. 1.2CUCh. 1 - Prob. 1.3CUCh. 1 - Prob. 1.4CUCh. 1 - Prob. 1.5CUCh. 1 - Prob. 1.6CUCh. 1 - Prob. 1.7CUCh. 1 - Prob. 1.8CUCh. 1 - Prob. 1.9CUCh. 1 - Prob. 1.10CUCh. 1 - Prob. 1.11CUCh. 1 - Prob. 1.12CUCh. 1 - Prob. 1.13CUCh. 1 - Prob. 1.14CUCh. 1 - Prob. 1.15CUCh. 1 - Prob. 1.16CUCh. 1 - Prob. 1.17CUCh. 1 - Prob. 1.18CUCh. 1 - Prob. 1.19CUCh. 1 - Prob. 1.20CUCh. 1 - Prob. 1.21CUCh. 1 - Prob. 1.22CUCh. 1 - Prob. 1.23CUCh. 1 - Prob. 1.24CUCh. 1 - Prob. 1.25CUCh. 1 - Prob. 1.26CUCh. 1 - Prob. 1.27CUCh. 1 - Prob. 1.28CUCh. 1 - Prob. 1.29CUCh. 1 - Prob. 1.30CUCh. 1 - Prob. 1.31CUCh. 1 - Prob. 1.32CUCh. 1 - Prob. 1.33CUCh. 1 - Prob. 1.34CUCh. 1 - Prob. 1.35CUCh. 1 - Prob. 1.36CUCh. 1 - Prob. 1.37CUCh. 1 - Prob. 1.38CUCh. 1 - Prob. 1.39CUCh. 1 - Prob. 1.40CUCh. 1 - Prob. 1.41CUCh. 1 - Prob. 1.42CUCh. 1 - Prob. 1.43CUCh. 1 - Prob. 1.44CUCh. 1 - Prob. 1.45CUCh. 1 - Prob. 1.46CUCh. 1 - Prob. 1.47CUCh. 1 - Prob. 1.48CUCh. 1 - Prob. 1.49CUCh. 1 - Prob. 1.50CUCh. 1 - Prob. 1.51CUCh. 1 - Prob. 1.52CUCh. 1 - Prob. 1.53CUCh. 1 - Prob. 1.54CUCh. 1 - Prob. 1.55CUCh. 1 - Prob. 1.56CUCh. 1 - Prob. 1.57CUCh. 1 - Prob. 1.58CUCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10PCh. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49P
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- The figure A1(a) shows the pressure of a gas that it is measured by use of a manometer The manometer liquid is water and h, =0.56 m. The reading on a nearby barometer is 0.78m of mercury. The density of mercury is 13.6x103 kg/m³. Calculate: a) The atmospheric pressure expressed in N/m?. b) The absolute gas pressure (p) expressed in N/m?. Pațmos Gas at pressure h, Figure A1(a)arrow_forwardAn open tube mercury manometer is used to measure the pressure in an oxygen tank. When the atmospheric pressure is 1040 mbar, what is the absolute pressure (in Pascal) in the tank if the height of the mercury in the open tube is 28 cm higher? (density of mercury = 13.6 X 10° kg/m³) * O 1.41 X10 pa O 2.34 X105 pa O 1.82 X105 pa O 2.12 X105 paarrow_forwardA manometer measures a pressure difference as 40 inches of water. What is this pressure difference in poundforce per square inch, psi?arrow_forward
- 5. If 10 m3 of atmospheric air at zero degrees centigrade temperature are compressed to a volume of 1 m3 at 100oC, what will be the pressure of air in kPa? (3 DECIMALS IN FINAL ANSWER PLS)arrow_forwardTwo (2) water reservoirs are connected to each other, as shown below. If the pressure difference between the two tanks is 21.6 kPa, calculate the value of "a" in mm. Water A Water 26.8 cm 2a B Mercury SG = 13.6 Note: Round-off only on your final answer, in four decimal places.arrow_forward1.) While the pressure remains constant at 100 psia the volume of a system of air changes from 20 ft' to 10 ft'. What are (a) AU in Btu, (b) Q in Btu, (c) Wn, Btuarrow_forward
- T F The specific weight of a fluid is the product of the fluid's density and the acceleration due to gravity. Stronger surface tension leads to higher capillary rise. Absolute pressures are frequently negative. If the pressure of fluid drops below the vapor pressure of that fluid at that temperature, the fluid will cavitate. F F T F F Density can be measured in lb;/ft° in the English system of units. For a hydrostatic incompressible fluid, pressure is independent of depth. A fluid with a high bulk modulus of elasticity is more difficult to compress than one with a low bulk modulus of elasticity. Viscosity is caused, in part, by the surface tension within a fluid. A fluid can resist an applied shear stress by deforming. Pressure increases faster with depth in less dense fluids than in more dense fluids. T F F F F Farrow_forwardAnswer number 4arrow_forwardTank B Pam= 101 kPa iv) Figure shows a tank within a tank, each containing air. The absolute pressure in tank A is 267.7 kPa. Pressure gage A is located inside of tank B and reads 140 kPa. The U-tube manometer connected to tank B contains mercury. Determine the absolute pressure in tank B, in kPa and column length, in cm. The atmospheric pressure surrounding tank B is 101 kPa. The acceleration due to gravity is 9.81 m/s?. Tank A. PA - 267.7 kPa Gage A Poen. A140 kPa Mercury (p 13.59 g/em) g=98i misarrow_forward
- A pressure of 35 kpa is measured 4m below the surface of an unknown liquid. what is the specific gravity of the liquid?arrow_forwardIf the specific gravity of unknown fluid is 13.56, what is its specific weight in lbf/ft³?arrow_forwardP1.4 A gas is contained in a cylinder behind a frictionless piston of diameter 0.1 m and mass 25 kg. When an additional mass M is placed on the piston the gage pressure of the gas becomes 2.0 bar. The local barometric pressure is 775 mm of mercury. (a) Calculate (i) the mass of M and (ii) the absolute pressure of the gas in the cylinder. (b) The piston is held in this position with the aid of a lock on the outside while heat is supplied to the gas until its absolute pressure becomes 4 bar. Calculate the force on the lock in the final equilibrium state. [Answers: (a) (i) 135 kg, (ii) 3.034 bar, (b) 758 N]arrow_forward
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