Chapter 1, Problem 1.35P

Interpretation Introduction

Interpretation:

Density of $53.4\text{ wt\%}$ aqueous sodium hydroxide has to be calculated if $16.7\text{ mL}$ of the solution diluted to $\text{2}\text{.00 L}$ giving $0.169M\text{ NaOH}\text{.}$

Concept introduction:

Molarity is a concentration term that is used to express the concentration of the solute in solution.  It is represented as,

$molarity\text{ = }\frac{no.of\text{ moles of solute}}{volume\text{ of solution in L}}$

Weight percent is one of parameters used to express concentration of a solution.  It is expressed as,

$\text{Weight percent of a solute = }\frac{\text{weight of solute}}{\text{weight of solution}}\times \text{ 100\%}$