Chapter 1, Problem 1.33FU

Interpretation Introduction

Interpretation: To determine the percentage of 120 g of ethylene glycol in 450 g liquid.

Concept introduction:

If there is component A in a liquid mixture, then the percentage of component A can be calculated as follows:

  $\text{percentage}\text{of}\text{component}\text{A}\text{=}\frac{\text{mass}\text{of}\text{component}\text{A}\text{in}\text{mixture}}{\text{total}\text{mass}\text{of}\text{mixture}}\times 100$

Answer to Problem 1.33FU

Percentage of ethylene glycol in mixture = 26.7 %.

Explanation of Solution

According to question:

Mass of ethylene glycol = 120 g

Mass of liquid = 450 g

Therefore,

  $\begin{array}{l}\text{percentage}\text{of}\text{ethylene }\text{glycol}\text{=}\frac{\text{mass}\text{of}\text{ethylene}\text{glycol}\text{in}\text{liquid}}{\text{Total}\text{mass}\text{of}\text{liquid}}\times 100\\ \Rightarrow \text{percentage}\text{of}\text{ethylene }\text{glycol}\text{=}\frac{120}{450}\times 100=26.7\%\end{array}$

Conclusion

26.7 % is the percentage of ethylene glycol in liquid mixture.