Biochemistry
Biochemistry
6th Edition
ISBN: 9781305577206
Author: Reginald H. Garrett, Charles M. Grisham
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 1, Problem 12P

Answers to all problems are at the end of this book. Detailed solutions are available in the Student Solutions Manual, Study Guide, and Problems Book.

A Simple Genome and Its Protein-Encoding Capacity The genome of the Mycoplasma genitalium consists of 523 genes, encoding 484 proteins, in just 5S0.U74 base pairs (see Table 1.6). What fraction of the M. genitalium genes encode proteins? What do you think the other genes encode? If the fraction of base pairs devoted to protein-coding genes is the same as the fraction of the total genes that they represent, what is tlie average number of base pairs per protein-coding gene? If it takes three base pairs to specify an amino acid in a protein, how many amino acids are found in the average M. genitalium protein? If each amino acid contributes, on average, 12U daltons to the mass of a protein, what is the mass of an average M. genitalium protein? (Section 1.5)

Blurred answer
Students have asked these similar questions
The preferred substrate is T because the enzyme half-saturates at 7.00 mM for T, but requires 28.0 mM for U, and 112 mM for S. b Question Content Area The rate constant k 2 with substrate S is 9.60×107 sec-1, with substrate T, k 2 = 6.00×104 sec-1, and with substrate U, k 2 = 2.40×106 sec-1. Calculate the catalytic efficiency with S, T, and U. Catalytic efficiency with S =  Catalytic efficiency with T =   Catalytic efficiency with U =   Does enzyme A use substrate S, substrate T, or substrate U with greater catalytic efficiency?
Fumerase catalyzes the conversion of fumerate to malate. fumerate + H2O ⇋ malate The turnover number, kcat, for fumerase is 8.00×102 sec-1. The Km of this enzyme for fumerate is 5.00×10-3 μmol mL-1.   a   In an experiment using 2.00×10-3 μmol·mL-1, what is Vmax?
Suppose you wanted to make a buffer of exactly pH 7.00 using KH2PO4 and Na2HPO4. If the final solution was 0.18 M in KH2PO4, you would need 0.25 M Na2HPO4. Now assume you wish to make a buffer at the same pH, using the same substances, but want the total phosphate molarity ([HPO42−]+[H2PO−4]) to equal 0.20 M. What concentration of the Na2HPO4 would be required?
Knowledge Booster
Background pattern image
Biochemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biochemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
  • Text book image
    Biochemistry
    Biochemistry
    ISBN:9781305577206
    Author:Reginald H. Garrett, Charles M. Grisham
    Publisher:Cengage Learning
Text book image
Biochemistry
Biochemistry
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Cengage Learning
Chapter 7 - Human Movement Science; Author: Dr. Jeff Williams;https://www.youtube.com/watch?v=LlqElkn4PA4;License: Standard youtube license