The rise in the capillary tubeat 40 ° C for a water-air-glass interface is to be calculated. Concept introduction: The surface tension in N / m as the function of temperature is given as: σ = 0 .123 ( 1 − 0.00139 T ) The upward force due to surface tension will be equal to the downward force due to the weight of liquid. The capillary rise is given as: h = 2 σ cos θ ρ g r Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

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Answer 1

Question

Chapter 1, Problem 1.26P

Interpretation Introduction

Interpretation: The rise in the capillary tubeat 40 °C for a water-air-glass interface is to be calculated.

Concept introduction:

The surface tension in N/m as the function of temperature is given as:

σ = 0.123(1−0.00139T)

The upward force due to surface tension will be equal to the downward force due to the weight of liquid.

The capillary rise is given as:

h = 2σcosθρgr

Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

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Answer 2

Question

Chapter 1, Problem 1.26P

Interpretation Introduction

Interpretation: The rise in the capillary tubeat 40 °C for a water-air-glass interface is to be calculated.

Concept introduction:

The surface tension in N/m as the function of temperature is given as:

σ = 0.123(1−0.00139T)

The upward force due to surface tension will be equal to the downward force due to the weight of liquid.

The capillary rise is given as:

h = 2σcosθρgr

Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

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Answer 3

Question

Chapter 1, Problem 1.26P

Interpretation Introduction

Interpretation: The rise in the capillary tubeat 40 °C for a water-air-glass interface is to be calculated.

Concept introduction:

The surface tension in N/m as the function of temperature is given as:

σ = 0.123(1−0.00139T)

The upward force due to surface tension will be equal to the downward force due to the weight of liquid.

The capillary rise is given as:

h = 2σcosθρgr

Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

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Answer 4

Question

Chapter 1, Problem 1.26P

Interpretation Introduction

Interpretation: The rise in the capillary tubeat 40 °C for a water-air-glass interface is to be calculated.

Concept introduction:

The surface tension in N/m as the function of temperature is given as:

σ = 0.123(1−0.00139T)

The upward force due to surface tension will be equal to the downward force due to the weight of liquid.

The capillary rise is given as:

h = 2σcosθρgr

Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

Expert Solution & Answer

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Answer 5

Chapter 1, Problem 1.26P

Interpretation Introduction

Interpretation: The rise in the capillary tubeat 40 °C for a water-air-glass interface is to be calculated.

Concept introduction:

The surface tension in N/m as the function of temperature is given as:

σ = 0.123(1−0.00139T)

The upward force due to surface tension will be equal to the downward force due to the weight of liquid.

The capillary rise is given as:

h = 2σcosθρgr

Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

Answer 6

Chapter 1, Problem 1.26P

Interpretation Introduction

Interpretation: The rise in the capillary tubeat 40 °C for a water-air-glass interface is to be calculated.

Concept introduction:

The surface tension in N/m as the function of temperature is given as:

σ = 0.123(1−0.00139T)

The upward force due to surface tension will be equal to the downward force due to the weight of liquid.

The capillary rise is given as:

h = 2σcosθρgr

Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

Answer 7

Chapter 1, Problem 1.26P

Interpretation Introduction

Interpretation: The rise in the capillary tubeat 40 °C for a water-air-glass interface is to be calculated.

Concept introduction:

The surface tension in N/m as the function of temperature is given as:

σ = 0.123(1−0.00139T)

The upward force due to surface tension will be equal to the downward force due to the weight of liquid.

The capillary rise is given as:

h = 2σcosθρgr

Here, σ is the surface tension, θ is the contact angle, ρ is the density of the liquid, g is the acceleration due to gravity, and r is the radius of the tube.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 1 - Prob. 1.1P Ch. 1 - Prob. 1.2P Ch. 1 - Prob. 1.3P Ch. 1 - Prob. 1.4P Ch. 1 - Prob. 1.5P Ch. 1 - Prob. 1.6P Ch. 1 - Prob. 1.7P Ch. 1 - Prob. 1.8P Ch. 1 - Prob. 1.9P Ch. 1 - Prob. 1.10P

Solution Summary: The author calculates the rise in the capillary tube for a water-air-glass interface.

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Chapter 1 Solutions