DATABASE CONCEPTS CUSTOM
DATABASE CONCEPTS CUSTOM
8th Edition
ISBN: 9780134639864
Author: KROENKE
Publisher: PEARSON C
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Chapter 1, Problem 1.18RQ

Explanation of Solution

Components of Database system:  

The database system constitutes of the key parts mentioned below:

  • DBMS (Database management system)
  • Database
  • Database application
  • User

Database management system:

  • Database management system is a set or collection of programs also known as system software which enables users to create, process, and administer the database.
  • It acts as an intermediary between programs and data.
  • Programs can get the access over data only through database management system which also maintains the required features of the data.

Database:

  • Database is defined as the organized set of tables, views, and other elements...

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Convert this question to Subroutines ORG 100 LDA A1 STA T1 LDA B1 STA T2 LDA T1 I STA A1 I ISZ B1 ISZ A1 ISZ ENC BUN L2 //COMPUTER HLT L1, INC A1, HEX 5000 STA T2 1 B1, HEX 6000 ISZ T1 T1, HEX O ISZ T2 T2, HEX 0 ISZ DCD DCD, DEC -8 BUN L1 // DPNQVUFS ENC, DEC -8 LDA B1 I DEC, HEX FF L2, ADD DEC END
Convert this question to Subroutines > F = [(A. B) + (A'. B')]” = [(A. B)'. (A'. B')']' ORG 100 LDA A // Load A operand to AC HLT // END Program AND B CMA STA T1 LDA A CMA STA T2 LDA B CMA AND T2 CMA // Store AC result in T1 // Load A operand to AC // Complement result in AC // Store AC [A'] result in T2 // Load B operand to AC // Complement result in AC // AND B' with T2[A'] operand // Complement result in AC AND T1 // AND [(A'.B')'] with T1[(A.B)'] CMA // Complement result in AC STA F // Store AC result in F // AND A operand with B operand B, HEX 01 // Complement result in AC A, HEX 01 T1, HEX O T2, HEX 0 F, HEX 0 END
Convert this question to Subroutines L1, L2, ORG 100 SKI BUN L1 INP OUT STA CTR CLA // Check input operation ready // Loop back to L1 location // Enter counter (-10) to AC // display counter operand // Store counter in CTR // Clear AC STA LOCI // Clear content of location LOC ISZ LOC ISZ CTR BUN L2 // Go to next Address // Check loop duration // Loop back to L2 location // End program HLT CTR, HEX 0 LOC, HEX 0150 END
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