FUND OF ENG THERMODYN-WILEYPLUS NEXT GEN
9th Edition
ISBN: 9781119840589
Author: MORAN
Publisher: WILEY
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Chapter 1, Problem 1.12CU
To determine
The difference between the specific volume in terms of mass basis and molar basis.
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assignment in Blackboard.
missing information to present a completed program. (Hint: You may have to look up geometry
for the center drill and standard 0.5000 in twist drill to know the required depth to drill).
1. What are the x and y dimensions for the center position of holes 1,2, and 3 in the part shown in
Figure 26.2 (below)?
6.0000
Zero
reference
point
7118
1.0005
1.0000
1.252
Bore
6.0000
.7118
Cbore
0.2180 deep
(3 holes)
2.6563 1.9445
Figure 26.2
026022 (8lot and Drill Part)
(Setup Instructions---
(UNITS: Inches
(WORKPIECE NAT'L SAE 1020 STEEL
(Workpiece: 3.25 x 2.00 x0.75 in. Plate
(PRZ Location 054:
'
XY 0.0 - Upper Left of Fixture
TOP OF PART 2-0
(Tool List
( T02 0.500 IN 4 FLUTE FLAT END MILL
#4 CENTER DRILL
Dashed line indicates-
corner of original stock
( T04
T02
3.000 diam. slot
0.3000 deep.
0.3000 wide
Intended toolpath-tangent-
arc entry and exit sized to
programmer's judgment…
A program to make the part depicted in Figure 26.A has been created, presented in figure 26.B, but some information still needs to be filled in. Compute the tool locations, depths, and other missing information to present a completed program. (Hint: You may have to look up geometry for the center drill and standard 0.5000 in twist drill to know the required depth to drill).
We consider a laminar flow induced by an impulsively started infinite flat
plate. The y-axis is normal to the plate. The x- and z-axes form a plane parallel
to the plate. The plate is defined by y = 0. For time t <0, the plate and the flow
are at rest. For t≥0, the velocity of the plate is parallel to the 2-coordinate;
its value is constant and equal to uw. At infinity, the flow is at rest. The flow
induced by the motion of the plate is independent of z.
(a) From the continuity equation, show that v=0 everywhere in the flow and
the resulting momentum equation is
მu
Ət
Note that this equation has the form of a diffusion equation (the same form as
the heat equation).
(b) We introduce the new variables T, Y and U such that
T=kt, Y=k/2y, U = u
where k is an arbitrary constant. In the new system of variables, the solution
is U(Y,T). The solution U(Y,T) is expressed by a function of Y and T and the
solution u(y, t) is expressed by a function of y and t. Show that the functions are
identical.…
Chapter 1 Solutions
FUND OF ENG THERMODYN-WILEYPLUS NEXT GEN
Ch. 1 - Prob. 1.2ECh. 1 - Prob. 1.3ECh. 1 - Prob. 1.4ECh. 1 - Prob. 1.5ECh. 1 - Prob. 1.6ECh. 1 - Prob. 1.7ECh. 1 - Prob. 1.8ECh. 1 - Prob. 1.9ECh. 1 - Prob. 1.10ECh. 1 - Prob. 1.11E
Ch. 1 - Prob. 1.12ECh. 1 - Prob. 1.13ECh. 1 - Prob. 1.14ECh. 1 - Prob. 1.1CUCh. 1 - Prob. 1.2CUCh. 1 - Prob. 1.3CUCh. 1 - Prob. 1.4CUCh. 1 - Prob. 1.5CUCh. 1 - Prob. 1.6CUCh. 1 - Prob. 1.7CUCh. 1 - Prob. 1.8CUCh. 1 - Prob. 1.9CUCh. 1 - Prob. 1.10CUCh. 1 - Prob. 1.11CUCh. 1 - Prob. 1.12CUCh. 1 - Prob. 1.13CUCh. 1 - Prob. 1.14CUCh. 1 - Prob. 1.15CUCh. 1 - Prob. 1.16CUCh. 1 - Prob. 1.17CUCh. 1 - Prob. 1.18CUCh. 1 - Prob. 1.19CUCh. 1 - Prob. 1.20CUCh. 1 - Prob. 1.21CUCh. 1 - Prob. 1.22CUCh. 1 - Prob. 1.23CUCh. 1 - Prob. 1.24CUCh. 1 - Prob. 1.25CUCh. 1 - Prob. 1.26CUCh. 1 - Prob. 1.27CUCh. 1 - Prob. 1.28CUCh. 1 - Prob. 1.29CUCh. 1 - Prob. 1.30CUCh. 1 - Prob. 1.31CUCh. 1 - Prob. 1.32CUCh. 1 - Prob. 1.33CUCh. 1 - Prob. 1.34CUCh. 1 - Prob. 1.35CUCh. 1 - Prob. 1.36CUCh. 1 - Prob. 1.37CUCh. 1 - Prob. 1.38CUCh. 1 - Prob. 1.39CUCh. 1 - Prob. 1.40CUCh. 1 - Prob. 1.41CUCh. 1 - Prob. 1.42CUCh. 1 - Prob. 1.43CUCh. 1 - Prob. 1.44CUCh. 1 - Prob. 1.45CUCh. 1 - Prob. 1.46CUCh. 1 - Prob. 1.47CUCh. 1 - Prob. 1.48CUCh. 1 - Prob. 1.49CUCh. 1 - Prob. 1.50CUCh. 1 - Prob. 1.51CUCh. 1 - Prob. 1.52CUCh. 1 - Prob. 1.53CUCh. 1 - Prob. 1.54CUCh. 1 - Prob. 1.55CUCh. 1 - Prob. 1.56CUCh. 1 - Prob. 1.57CUCh. 1 - Prob. 1.58CUCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10PCh. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49P
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- Part A: Suppose you wanted to drill a 1.5 in diameter hole through a piece of 1020 cold-rolled steel that is 2 in thick, using an HSS twist drill. What values if feed and cutting speed will you specify, along with an appropriate allowance? Part B: How much time will be required to drill the hole in the previous problem using the HSS drill?arrow_forward1.1 m 1.3 m B 60-mm diameter Brass 40-mm diameter Aluminum PROBLEM 2.52 - A rod consisting of two cylindrical portions AB and BC is restrained at both ends. Portion AB is made of brass (E₁ = 105 GPa, α = 20.9×10°/°C) and portion BC is made of aluminum (Ę₁ =72 GPa, α = 23.9×10/°C). Knowing that the rod is initially unstressed, determine (a) the normal stresses induced in portions AB and BC by a temperature rise of 42°C, (b) the corresponding deflection of point B.arrow_forward30 mm D = 40 MPa -30 mm B C 80 MPa PROBLEM 2.69 A 30-mm square was scribed on the side of a large steel pressure vessel. After pressurization, the biaxial stress condition at the square is as shown. For E = 200 GPa and v=0.30, determine the change in length of (a) side AB, (b) side BC, (c) diagnonal AC.arrow_forward
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