Chemistry
4th Edition
ISBN: 9780393919370
Author: Thomas R. Gilbert
Publisher: NORTON
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Chapter 1, Problem 1.11QP
Interpretation Introduction
Interpretation: The method that is used to separate the mixture of salt and sand through filtration process is to be stated.
Concept introduction: The process of filtration is used to separate solid from fluids by adding some medium that permits the fluid to pass through but retains the solid substance.
To determine: The method that is used to separate the mixture of salt and sand through filtration process.
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PROBLEM 5+
What is the major product of each of the following reactions?
a. CH3CH2CHCH3 + HBr
d.
+ HBr
A
OH
OH
CH3
CH3
e.
b.
-OH + HCI
+ HCl
A,
OH
CH3
OH
CH3
c. CH3C CHCH3 + HBr
CH3 OH
f.
CHCH3 + HCl ^>
One suggestion for solving the fuel shortage due to decreasing volumes of fossil fuels
are hydrogen / oxygen fuel cells.
a. State the two half-cell reaction equations for such fuel cells. Calculate the cell
potential as well as the electrical work gained by this fuel cell at standard conditions
with E002/H20 = 1.229 V.
b. Compare the fuel cell to the Gibbs free energy of the combustion reaction of
n-octane at standard conditions. Use ASºm, n-Oct., 1 = 361.2 J/mol K.
a. Determine the electrochemical potential of the following cell using
E°Mg2+/Mg = -2.362 V.
Mg | Mg2+ (a=104) || H* (a = 4) | H2 (p
= 0.5 bar) | Pt
b. A galvanic chain consists of Co²+ / Co and Ag+ / Ag half-cells with
EºCo²+/Co = -0.282 V and Eº Ag+/Ag = 0.799 V. Determine which half-cell will be
reduced and which one will be oxidised. Furthermore, calculate the electrochemical
potential as well as the equilibrium constant of the whole cell at
i. [Co²+] = 0.1 M and [Ag+] = 0.5 M
ii. [Co²+] = 0.001 M and [Ag*] = 1.5 M
Chapter 1 Solutions
Chemistry
Ch. 1.5 - Prob. 1PECh. 1.6 - Prob. 2PECh. 1.8 - Prob. 3PECh. 1.8 - Prob. 4PECh. 1.8 - Prob. 5PECh. 1.9 - Prob. 6PECh. 1.9 - Prob. 7PECh. 1 - Prob. 1.1VPCh. 1 - Prob. 1.2VPCh. 1 - Prob. 1.3VP
Ch. 1 - Prob. 1.4VPCh. 1 - Prob. 1.5VPCh. 1 - Prob. 1.6VPCh. 1 - Prob. 1.7QPCh. 1 - Prob. 1.8QPCh. 1 - Prob. 1.9QPCh. 1 - Prob. 1.10QPCh. 1 - Prob. 1.11QPCh. 1 - Prob. 1.12QPCh. 1 - Prob. 1.13QPCh. 1 - Prob. 1.14QPCh. 1 - Prob. 1.15QPCh. 1 - Prob. 1.16QPCh. 1 - Prob. 1.17QPCh. 1 - Prob. 1.18QPCh. 1 - Prob. 1.19QPCh. 1 - Prob. 1.20QPCh. 1 - Prob. 1.21QPCh. 1 - Prob. 1.22QPCh. 1 - Prob. 1.23QPCh. 1 - Prob. 1.24QPCh. 1 - Prob. 1.25QPCh. 1 - Prob. 1.26QPCh. 1 - Prob. 1.27QPCh. 1 - Prob. 1.28QPCh. 1 - Prob. 1.29QPCh. 1 - Prob. 1.30QPCh. 1 - Prob. 1.31QPCh. 1 - Prob. 1.32QPCh. 1 - Prob. 1.33QPCh. 1 - Prob. 1.34QPCh. 1 - Prob. 1.35QPCh. 1 - Prob. 1.36QPCh. 1 - Prob. 1.37QPCh. 1 - Prob. 1.38QPCh. 1 - Prob. 1.39QPCh. 1 - Prob. 1.40QPCh. 1 - Prob. 1.41QPCh. 1 - Prob. 1.42QPCh. 1 - Prob. 1.43QPCh. 1 - Prob. 1.44QPCh. 1 - Prob. 1.45QPCh. 1 - Prob. 1.46QPCh. 1 - Prob. 1.47QPCh. 1 - Prob. 1.48QPCh. 1 - Prob. 1.49QPCh. 1 - Prob. 1.50QPCh. 1 - Prob. 1.51QPCh. 1 - Prob. 1.52QPCh. 1 - Prob. 1.53QPCh. 1 - Prob. 1.54QPCh. 1 - Prob. 1.55QPCh. 1 - Prob. 1.56QPCh. 1 - Prob. 1.57QPCh. 1 - Prob. 1.58QPCh. 1 - Prob. 1.59QPCh. 1 - Prob. 1.60QPCh. 1 - Prob. 1.61QPCh. 1 - Prob. 1.62QPCh. 1 - Prob. 1.63QPCh. 1 - Prob. 1.64QPCh. 1 - Prob. 1.65QPCh. 1 - Prob. 1.66QPCh. 1 - Prob. 1.67QPCh. 1 - Prob. 1.68QPCh. 1 - Prob. 1.69QPCh. 1 - Prob. 1.70QPCh. 1 - Prob. 1.71QPCh. 1 - Prob. 1.72QPCh. 1 - Prob. 1.73QPCh. 1 - Prob. 1.74QPCh. 1 - Prob. 1.75QPCh. 1 - Prob. 1.76QPCh. 1 - Prob. 1.77QPCh. 1 - Prob. 1.78QPCh. 1 - Prob. 1.79QPCh. 1 - Prob. 1.80QPCh. 1 - Prob. 1.81QPCh. 1 - Prob. 1.82QPCh. 1 - Prob. 1.83QPCh. 1 - Prob. 1.84QPCh. 1 - Prob. 1.85QPCh. 1 - Prob. 1.86QPCh. 1 - Prob. 1.87QPCh. 1 - Prob. 1.88QPCh. 1 - Prob. 1.89APCh. 1 - Prob. 1.90APCh. 1 - Prob. 1.91APCh. 1 - Prob. 1.92APCh. 1 - Prob. 1.93APCh. 1 - Prob. 1.94APCh. 1 - Prob. 1.95APCh. 1 - Prob. 1.96APCh. 1 - Prob. 1.97APCh. 1 - Prob. 1.98APCh. 1 - Prob. 1.99APCh. 1 - Prob. 1.100AP
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