(a)
Interpretation:
The application of the two specific examples of metals as a regular part of the life needs to be explained.
Concept Introduction:
Different materials have different properties which best suits the particular application. Metals are an element that produces positive ions by losing electrons. They have high strength due to their rigid structure. Generally, metals are solid at room temperature. The only metal which is liquid at room temperature is mercury.
(b)
Interpretation:
The application of the two specific examples of ceramics as a regular part of the life needs to be explained.
Concept Introduction:
Different materials have different properties which best suits the particular application. Ceramics are made up of combining two or more metals or nonmetals.
(c)
Interpretation:
The application of the two specific examples of polymers as a regular part of the life needs to be explained.
Concept Introduction:
Different materials have different properties which best suits the particular application. Polymers are organic materials made by polymerization.
(d)
Interpretation:
The application of the two specific examples of semiconductors as a regular part of the life needs to be explained.
Concept Introduction:
Different materials have different properties which best suits the particular application. Semiconductors are material having electrical conductivity between conductors and insulators.
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Chapter 1 Solutions
Essentials Of Materials Science And Engineering, Si Edition
- In order to solve the frame given below with the Force Method, remove restraints from joints A and G and draw only the bending moment diagrams Mo, M₁, M2 and M3 for this case. (25 Pts.) Note: Only bending moment diagrams that are used for the solution are required. There is no need to do any further calculations. 4 kN B I E D 2 kN/m H 3 m 3 m 4 m + 2 m 4marrow_forwardplease show complete solution with formulaarrow_forwardb = 25 y t = 2 a=10 C = 25arrow_forward
- please show complete solution, thank youarrow_forwardA left-sided signal x(t)=-ebt u(-t): A right-sided signal x(t)=e¯at u(t) Find Laplace transform of x(t)=u(t)arrow_forwardreading is 0.4 mas SHOWN. Assume h₁ = 0.4 m, h₂ = 0.5 m. (a) Do you know the specific weight of mercury? (b) Do you know the specific weight of gasoline? (c) Do you know the specific weight of oil? (a) YHg = 133,000 (b) Ygas = 6867 (c) Yoil = 8829 eTextbook and Media Part 2 N/m³ N/m³ N/m³ A+ Gasoline t +B Oil -Mercury Attempts: unlimited Did you calculate the pressure difference between two locations using the correct specific weight? Did you assume that the pressures in fluid are the same in a horizontal plane even though they are in different tubes? Are the calculated pressures in a column of fluid always higher at lower elevations? Did you account for the fact that the two horizontal tubes of the U-tube are above the ground? Concepts: The pressure in a fluid is a function of the specific weight of the fluid and the height relative to a reference. Pressure is constant in a horizontal plane of a continuous mass of fluid. (a) What is the initial pressure difference? (PA-PB) (b) What is…arrow_forward
- Find the solution of the following Differential Equations 1) "-4y+3y=0 3) "+16y=0 2) y"-16y=0 4) y"-y-6y=0 5) y"+2y=0 7) y"+y=0, (#0) 9) y"-y=0, y(0) = 6, y'(0) = -4 11) y"-4y+3y=0, y(0)=-1, 13) y'(0) = -5 "+2y+2y=0 15) y"-9y=0 17) y"-4y=0 6) y"-2y+2y=0 8) "+4y+5y=0 10) y"-9y=0, y(0) = 2, y'(0) = 0 12) y"-3y+2y= 0, y(0)=-1, y'(0) = 0 14) 4y+4y+y=0 16) "+6y+12y=0 18) 4y+4y+17y=0arrow_forwardFind Laplace transform of x(t) = −e¯btu(−t) + e¯atu(t) Find Laplace transform of x(t) = u(t)arrow_forwardplease show complete solution, step by step, thanksarrow_forward
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