The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold. Concept introduction: Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors. The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship. The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation. 1 L is 1000 mL , conversion factor is as: 10 3 mL 1 L .

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Answer 1

Question

Chapter 1, Problem 103AP

Interpretation Introduction

Interpretation:

The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold.

Concept introduction:

Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors.

The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship.

The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation.

1L is 1000 mL, conversion factor is as: 103 mL1 L.

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Answer 2

Question

Chapter 1, Problem 103AP

Interpretation Introduction

Interpretation:

The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold.

Concept introduction:

Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors.

The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship.

The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation.

1L is 1000 mL, conversion factor is as: 103 mL1 L.

Expert Solution & Answer

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See solution

Answer 3

Question

Chapter 1, Problem 103AP

Interpretation Introduction

Interpretation:

The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold.

Concept introduction:

Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors.

The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship.

The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation.

1L is 1000 mL, conversion factor is as: 103 mL1 L.

Expert Solution & Answer

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Answer 4

Question

Chapter 1, Problem 103AP

Interpretation Introduction

Interpretation:

The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold.

Concept introduction:

Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors.

The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship.

The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation.

1L is 1000 mL, conversion factor is as: 103 mL1 L.

Expert Solution & Answer

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Answer 5

Chapter 1, Problem 103AP

Interpretation Introduction

Interpretation:

The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold.

Concept introduction:

Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors.

The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship.

The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation.

1L is 1000 mL, conversion factor is as: 103 mL1 L.

Answer 6

Chapter 1, Problem 103AP

Interpretation Introduction

Interpretation:

The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold.

Concept introduction:

Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors.

The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship.

The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation.

1L is 1000 mL, conversion factor is as: 103 mL1 L.

Answer 7

Chapter 1, Problem 103AP

Interpretation Introduction

Interpretation:

The total amount of gold present in seawater and the worth of the total gold in dollars is to be calculated. State the reason for not becoming rich by mining gold.

Concept introduction:

Dimensional analysis is used to set up and solve a unit conversion problem using conversion factors.

The conversion factor is a fraction obtained from a relationship between the units. It is written as a ratio and can be inverted to give two conversion factors for every relationship.

The appropriate conversion factor for any equality is selected in such a way so that it results in the proper unit cancellation.

1L is 1000 mL, conversion factor is as: 103 mL1 L.

Answer 8

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Answer 9

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Answer 10

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Answer 11

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Solution Summary: The author explains that the total amount of gold present in seawater is 6.0times 1012g and the worth of total gold in dollars.

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