(a) Explanation Given information: The expression, y 2 + y − 6 . Formula used: Steps to calculate the factors of quadratic equation a x 2 + b x + c by trial and error method, Step1: Factor a x 2 as ( a 1 x ) ( a 2 x ) with a 1 positive. Step2: Factor c as c 1 c 2 . Step 3: Check if a x 2 + b x + c = ( a 1 x ± c 1 ) ( a 2 x ± c 2 ) If yes, then ( a 1 x ± c 1 ) ( a 2 x ± c 2 ) are the factors. Step 4: If not, try other factorization of a x 2 and c and repeat all the steps. The distributive law, ( a ± b ) c = a c ± b c Where, a, b and c are any real numbers. Calculation: Consider the expression, y 2 + y − 6 Factor of y 2 are ( y ) ( y ) and factors of − 6 are ( 1 ) ( − 6 ) , ( − 1 ) ( 6 ) , ( 2 ) ( − 3 ) and ( − 2 ) ( 3 ) (b) To determine To calculate: The value of y when the expression y 2 + y − 6 is equal to zero.

7th Edition

ISBN: 9781337291248

Author: Waner, Stefan.

Publisher: Cengage Learning,

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Chapter 0.3, Problem 38E

(a)

To determine

To calculate: The factors of the expression y2+y−6.

(b)

To determine

To calculate: The value of y when the expression y2+y−6 is equal to zero.

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Chapter 0.3, Problem 37E

Chapter 0.3, Problem 39E

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5. [-/1 Points] DETAILS MY NOTES SESSCALCET2 6.5.AE.003. y y= ex² 0 Video Example x EXAMPLE 3 (a) Use the Midpoint Rule with n = 10 to approximate the integral कर L'ex² dx. (b) Give an upper bound for the error involved in this approximation. SOLUTION 8+2 1 L'ex² d (a) Since a = 0, b = 1, and n = 10, the Midpoint Rule gives the following. (Round your answer to six decimal places.) dx Ax[f(0.05) + f(0.15) + ... + f(0.85) + f(0.95)] 0.1 [0.0025 +0.0225 + + e0.0625 + 0.1225 e0.3025 + e0.4225 + e0.2025 + + e0.5625 €0.7225 +0.9025] The figure illustrates this approximation. (b) Since f(x) = ex², we have f'(x) = 0 ≤ f'(x) = < 6e. ASK YOUR TEACHER and f'(x) = Also, since 0 ≤ x ≤ 1 we have x² ≤ and so Taking K = 6e, a = 0, b = 1, and n = 10 in the error estimate, we see that an upper bound for the error is as follows. (Round your final answer to five decimal places.) 6e(1)3 e 24( = ≈

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Ch. 0.1 - Prob. 11E Ch. 0.1 - Prob. 12E Ch. 0.1 - Prob. 13E Ch. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 15E Ch. 0.1 - Prob. 16E Ch. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 18E Ch. 0.1 - Prob. 19E Ch. 0.1 - Prob. 20E Ch. 0.1 - Prob. 21E Ch. 0.1 - Prob. 22E Ch. 0.1 - Prob. 23E Ch. 0.1 - Prob. 24E Ch. 0.1 - Prob. 25E Ch. 0.1 - Prob. 26E Ch. 0.1 - Prob. 27E Ch. 0.1 - Prob. 28E Ch. 0.1 - Prob. 29E Ch. 0.1 - Prob. 30E Ch. 0.1 - Prob. 31E Ch. 0.1 - Prob. 32E Ch. 0.1 - Prob. 33E Ch. 0.1 - Prob. 34E Ch. 0.1 - Prob. 35E Ch. 0.1 - Prob. 36E Ch. 0.1 - Convert each expression in Exercises 25-50 into...Ch. 0.1 - Prob. 38E Ch. 0.1 - Prob. 39E Ch. 0.1 - Prob. 40E Ch. 0.1 - Prob. 41E Ch. 0.1 - Prob. 42E Ch. 0.1 - Prob. 43E Ch. 0.1 - Prob. 44E Ch. 0.1 - Prob. 45E Ch. 0.1 - Prob. 46E Ch. 0.1 - Prob. 47E Ch. 0.1 - Prob. 48E Ch. 0.1 - Prob. 49E Ch. 0.1 - Prob. 50E Ch. 0.2 - Evaluate the expression sin Exercises 116. 33 Ch. 0.2 - Prob. 2E Ch. 0.2 - Evaluate the expression sin Exercises 116. 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The factors of the expression y 2 + y − 6 .

Solution Summary: The author explains how to calculate the factors of the expression y2+y-6 by trial and error method.

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To calculate: The factors of the expression y2+y−6.

To calculate: The value of y when the expression y2+y−6 is equal to zero.

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