Zoos = 2.5758, Zot = 2.326, Z25 = 1.96, Zo5 = 1.645 Toos,s = -4.302, To1,5=-3.365, To255 -2.571, To5.5 = -2.015 Toos4= -4.605, To1,4 =-3.747, T025,4 = -2.776,To5,4 = -2.132 O 94.357 O 93.716 M&M's peanuts advertise that the average weight of their product is 100. overstated, don't have much money to test it, so sample 5 bags, with a mean of 95 and a standard We think that's deviation of 3.75. What would the maximum value of our sample mean have to be to cause us to reject the null hypothesis on the low side, at a 1% overall alpha level assuming normality? O 97.190 85.949

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Zoos = 2.5758, Zo1 = 2.326, Z025 = 1.96, Z.05 = 1.645
Toos.s=-4.302, Tos=-3.365, To25.5 = -2.571, Toss-2.015
Toos, 4 = -4.605, To1,4 =-3.747, T025,4 = -2.776, Tos,4 = -2.132
O 94.357
O 93.716
O 97.190
M&M's peanuts advertise that the average weight of their product is 100.
overstated, don't have much money to test it, so sample 5 bags, with a mean of 95 and a standard
We think that's
deviation of 3.75. What would the maximum value of our sample mean have to be to cause us
to reject the null hypothesis on the low side, at a 1% overall alpha level assuming normality?
O 85.949
O 96.099
Transcribed Image Text:Zoos = 2.5758, Zo1 = 2.326, Z025 = 1.96, Z.05 = 1.645 Toos.s=-4.302, Tos=-3.365, To25.5 = -2.571, Toss-2.015 Toos, 4 = -4.605, To1,4 =-3.747, T025,4 = -2.776, Tos,4 = -2.132 O 94.357 O 93.716 O 97.190 M&M's peanuts advertise that the average weight of their product is 100. overstated, don't have much money to test it, so sample 5 bags, with a mean of 95 and a standard We think that's deviation of 3.75. What would the maximum value of our sample mean have to be to cause us to reject the null hypothesis on the low side, at a 1% overall alpha level assuming normality? O 85.949 O 96.099
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