y=[w(1:6),0,0,3] Enter ans= 1 600 3<< Correct O Incorrect
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- If you type in the following formula into the cell E7: MMULT(C4:D5, C4 :D5), it will return \table[[, C,D,E ], [4, 2, 3,], [5, 4, 5, ], [6,,,], [7,,,], [8,,,]]//main.cpp file #include <iostream> #include "helper.h" #include "sorting.h" using namespace std; int main() { unsigned int size; cout << "Enter the size of the array: "; cin >> size; int* Array = new int[size]; unsigned int choice = 0; do { fillRandom(Array, size); cout << "Choose your sorting algorithm:" << endl; cout << "1. Bubble Sort" << endl; cout << "2. Selection Sort" << endl; cout << "3. Insertion Sort" << endl; cout << "4. Merge Sort" << endl; cout << "5. Quick Sort" << endl; cout << "6. Shell Sort" << endl; //Optional cout << "Enter 0 to exit" << endl; cout << "Your choice: "; cin >> choice; cout << "Unsorted Array: "; print(Array, size); /***************************** TODO: Implement what you will do with the choice*****************************/ cout << "Sorted Array: "; print(Array, size); } while(choice!=0); delete [] Array; return 0; }…What does the following code mean?: if r[i+1]
- This is the C code I have so far #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; struct employees **emps = new employees()[10]; //Added new statement ---- bartleby // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for(int i =0; i <9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct employees…Q1: complete the function that will return the multipication of 3 given numbers - a,b,c. In [ ]: def multiply_numbers(a,b,c): II II || """insert the code that performs the operation. Use the variable 'number' to hold and return the value II || || # your code here return number10. Let A = {c, n, b}, B = {x, y} and C = {0, 1}. Find a) АХВХС b) СХВХА c) BXCXC
- Declare a function named contains_char. Its purpose is when given two strings, the first of any length, the second a single character, it will return True if the single character of the second string is found at any index of the first string, and return False otherwise.#include <iostream> using namespace std; int main(){char *ptr;char Str[ ] ="abcdefg"; ptr =Str;ptr += 5;cout << ptr; return0;}a) fgb) cdefc) defgd) abcdbcdjs ssolution req
- void Q1_1() { } const int SIZE = 22; char value[] = ('c', 'e', 'E', 'p', '1', 'u', 's', 'P', 'L', ‘U', 'S'}; //ASCII code of A to Z is 65 to 90 cout<please use DEQUE #include <iostream>#include <string>#include <deque> using namespace std; const int AIRPORT_COUNT = 12;string airports[AIRPORT_COUNT] = {"DAL","ABQ","DEN","MSY","HOU","SAT","CRP","MID","OKC","OMA","MDW","TUL"}; int main(){// define stack (or queue ) herestring origin;string dest;string citypair;cout << "Loading the CONTAINER ..." << endl;// LOAD THE STACK ( or queue) HERE// Create all the possible Airport combinations that could exist from the list provided.// i.e DALABQ, DALDEN, ...., ABQDAL, ABQDEN ...// DO NOT Load SameSame - DALDAL, ABQABQ, etc .. cout << "Getting data from the CONTAINER ..." << endl;// Retrieve data from the STACK/QUEUE here } Using the attached shell program (AirportCombos.cpp), create a list of strings to process and place on a STL DEQUE container. Using the provided 3 char airport codes, create a 6 character string that is the origin & destination city pair. Create all the possible…#include <bits/stdc++.h>using namespace std;int main() { double matrix[4][3]={{2.5,3.2,6.0},{5.5, 7.5, 12.6},{11.25, 16.85, 13.45},{8.75, 35.65, 19.45}}; cout<<"Input no in first row of matrix"<<endl; for(int i=0;i<3;i++){ double t; cin>>t; matrix[0][i]=t; } cout<<"Contents of the last column in matrix"<<endl; for(int i=0;i<4;i++){ cout<<matrix[i][2]<<" "; } cout<<"Content of first row and last column element in matrix is: "<<matrix[0][3]<<endl; matrix[3][2]=13.6; cout<<"Updated matrix is :"<<endl; for(int i=0;i<4;i++){ for(int j=0;j<3;j++){ cout<<matrix[i][j]<<" "; }cout<<endl; } return 0;} Please explain this codeSEE MORE QUESTIONS