What is the maximum weekly profit? What is the maximum weekly profit? Round to the nearest dollar.O L CF8F9F10F11F4F5F6F7&6.8YUPト44 Yaster Outfitters manufactures and sells extreme-cold sleeping bags. The table below shows theprice-demand and total cost data, whereRevenue Modelpis the wholesale price (in dollars) of a sleeping bag for a weekly demand of a sleeping bags;Cis the total cost (in dollars) of producing r sleeping bags.Using the regression model computed above, find a model for the weekly revenue, using x as theindependent variable.z (sleeping bags)P (S)C (S)9524013.000NOTE: Do not calculate another regression. Use the price equation to find a model for revenue12023514,300R(x) = p· x.18015518,500R(x) = p.x = (a + bx + ca²)a= ar + bx² + cr³2205021.000Cost ModelFind a linear regression model for the weekly cost data, using x as the independent variable.Find a quadratic regression equation for the price-demand data, using x as the independent variable.C(x) = mx + kp= a+ bx + cx²Round m to 1 decimal place, and round k to the nearest integer.Round a to the nearest integer, round b to 2 decimal places, and round c to 4 decimal places.Profit ModelUse the models computed to find a model for the weekly profit, using x as the independent variable.The weekly profit model has roots at x =-52.789, x =47.555, and x = 202.944, rounded to 3P(z) =T+ux + sx2 + ta3decimal places.NOTE: Do not calculate another regression. Use the fact that profit is revenue minus cost.Round r to the nearest integer, round u to 1 decimal place, round s to 2 decimal places, and roundtThe marginal weekly profit model has roots at x = -8.488 and x =140.295, rounded to 3%3Dto 4 decimal places.decimal places.O wordsLO Accessibility: InvestigateOType here to searchD Focus目223%中口LC1:40 AM国77%11/17/2021F5F6F8F9F10PrtScInsertDeleteF11F124.BackspaceNumLockYUPIFH.00

Given information: Given data represents the values of the variables x = sleeping bags, p = price and c = cost.Find the cost model: EXCEL software can be used to plot a least squares line on a scatter diagram for the given data. Software Procedure: The step-by-step procedure to plot a least squares line on a scatter diagram using EXCEL software is given below: Open an EXCEL file. Enter the data of Sleeping bags in column A and name it as x. Enter the data of Cost in column B and name it as C. Select Data and go to Insert tab. Select Charts > All charts > Scatter (X Y). Click OK. Select any point on the Scatterplot and left click on it. Select add trendline > linear and click on display equation. The output is as shown below: The cost model is: C(x) = 65.2x + 6674.Find the profit model: EXCEL software can be used to plot a least squares line on a scatter diagram for the given data. Software Procedure: The step-by-step procedure to plot a least squares line on a scatter diagram using EXCEL software is given below: Open an EXCEL file. Enter the data of Sleeping bags in column A and name it as x. Enter the data of Price in column B and name it as p. Select Data and go to Insert tab. Select Charts > All charts > Scatter (X Y). Click OK. Select any point on the Scatterplot and left click on it. Select add trendline > polynomial > order = 2 and click on display equation. The output is as shown below: The price model is: p = 112 + 2.59x – 0.0131x2 Find the revenue model: The revenue model is as given below: R(x) = p*x = (112 + 2.59x – 0.0131x2)*x = 112x + 2.59x2 – 0.0131x3. Find the profit model: The profit model is: p(x) = R(x) – c(x) = 112x + 2.59x2 – 0.0131x3 – 65.2x – 6674 = 2.59x2 – 0.0131x3 + 46.8x – 6674 Find the maximum weekly profit: The maximum weekly profit is obtained as given below: p(x) = 2.59x2 – 0.0131x3 + 46.8x – 6674 p1(x) = 5.18x – 0.0393x2 + 46.8 = – 0.0393x2 + 5.18x + 46.8 p1(x) = 0 – 0.0393x2 + 5.18x + 46.8 = 0 0.0393x2 – 5.18x – 46.8 = 0 x = 140.295 and x = 8.48813 Maximum profit = 2.59*140.2952 – 0.0131*140.2953 + 46.8*140.295 – 6674 = 14696