Your team at the lab has developed a new and hopefully non-toxic liquid, named gloop by Marketing, to be used in swimming pools. Gloop is denser than water, so it provides more buoyancy for swimming. (1) An unwary visitor to the lab drops their tablet into an open tank of gloop. The gloop's density is 2480 kg/m3, and the tank is 9.05 m deep. Calculate the total pressure the tablet experiences at the bottom of the gloop tank. Keep in mind: we have an atmosphere! (2) The length L = 16.2 cm and width W = 8.48 for the tablet's screen (in SI units, to 3 SF), then calculate the force on the tablet's screen due to the pressure of the gloop. This is not a buoyant force! (3) Next, you'll be immersing a solid ball in gloop. The ball is plastic (m = 0.476 kg, radius r = 5.78 cm). Calculate the ball's density. Tip: convert units first. (4) Would the ball float or sink if dropped into the gloop? Explain in 1-2 sentences, but no further calculations. (5) If you found that the ball would float in gloop, you're now going to push down on it, holding it at rest completely submerged. Or, if you found that the ball would sink in the gloop, you're going to support the fully submerged ball to keep it from sinking farther. Draw a complete Free body diagram for the fully submerged ball. (6) Write down and solve Newton's second law to calculate the amount of force you exert on the ball when it's at rest and fully submerged. Tip: the force you exert is not the buoyant force, nor is that force equal to FB. (7) The gloop in the tank will now be pumped out through a hose. As it leaves the pump, the gloop flows through the hose at a speed of 4.33 m/s, and the hose diameter is 4.95 cm. At the other end of the hose is a nozzle with a diameter dn = 2.22 cm. Calculate the speed of the gloop spraying out of the nozzle. (8) The nozzle end of the hose is 8.91 m above the pump and open to the atmosphere. Calculate the pressure in the gloop at the pump end. Tips: this question builds on the previous one. No calculations are needed for the pressure at the nozzle end. The pressure calculated in #1 is completely unrelated to this question, and the eqn used there is also completely invalid here - this isn't just Question 1 with a new depth. Use subscripts carefully, and make sure you're clear about whether "1" means the nozzle end or the pump end, so that "2" will clearly mean the other end. Easiest on the brain: make those subscripts match your work in #7!