Learning Goal: Photoelectric Effect The work function of calcium metal is Wo = 2.71 eV. 1 electron volt (eV) = 1.6 x 1019 J. Part A - What is the energy of each photon in the incident light? Use h = 6.626x10-34 J.s for Planck's constant and c = 3.00x108 m/s for the Use scientific notations, format 1.234*10" unit is Joules speed of light in a vacuum. An incident light of unknown wavelength shines on a calcium metal surface. The max kinetic energy of the photoelectrons is 7.059x10-20 J ? photon energy = Submit Request Answer Part B - What is the wavelength of the incident light? Enter a regular number with 1 digit after the decimal point, in nm. 1nm = 10-9 m ? nm Submit Request Answer

Learning Goal: Photoelectric Effect The work function of calcium metal is Wo = 2.71 eV. 1 electron volt (eV) = 1.6 x 1019 J. Part A - What is the energy of each photon in the incident light? Use h = 6.626x10-34 J.s for Planck's constant and c = 3.00x108 m/s for the Use scientific notations, format 1.234*10" unit is Joules speed of light in a vacuum. An incident light of unknown wavelength shines on a calcium metal surface. The max kinetic energy of the photoelectrons is 7.059x10-20 J ? photon energy = Submit Request Answer Part B - What is the wavelength of the incident light? Enter a regular number with 1 digit after the decimal point, in nm. 1nm = 10-9 m ? nm Submit Request Answer