If y = f(x) is a polynomial function of degree 3, then The slope of the tangent line to the graph of y = In|x| at x = -; The slope of the normal line to the graph of f(x) = tanx at x = 7/3 is , f(x) n + 1" n + -1, then f'(x)

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can someone please answer these thank you

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If y = f(x) is a polynomial function of degree 3, then
The slope of the tangent line to the graph of y = In\x| at x =
is
The slope of the normal line to the graph of f(x) = tan.x at x = 7/3 is
f(x)
n+ 1" # -1, then f'(x) =
An equation of the tangent line to the graph of y = (x + 3)/(x – 2) at x = 0 is
For f(x) = 1/(1 – 3x) the instantaneous rate of change of f' with respect to x at x = 0
is
%3D
If f'(4) = 6 and g'(4) = 3, then the slope of the tangent line to the graph of
y = 2 f(x) – 5g(x) at x = 4 is
Transcribed Image Text:d If y = f(x) is a polynomial function of degree 3, then The slope of the tangent line to the graph of y = In\x| at x = is The slope of the normal line to the graph of f(x) = tan.x at x = 7/3 is f(x) n+ 1" # -1, then f'(x) = An equation of the tangent line to the graph of y = (x + 3)/(x – 2) at x = 0 is For f(x) = 1/(1 – 3x) the instantaneous rate of change of f' with respect to x at x = 0 is %3D If f'(4) = 6 and g'(4) = 3, then the slope of the tangent line to the graph of y = 2 f(x) – 5g(x) at x = 4 is
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