Your tasks Task 1: an exclusive-or gate In addition to AND and OR gates, one commonly also needs an XOR gate (meaning eXclusive-OR). Its graphical presentation as well as semantics are given in the following figure: 0 0 1 XOR XOR 0 1 1X09-1 XOR 1x0 XOR Your task is to implement the method buildXOR in gatetasks. scala which should return a gate forming an XOR operation on the two input gates. Task 2: a majority-of-three gate In many safety-critical applications one has to take into account that some of the components may fail for some reason. One way to cope (to a limited degree) with failures is to replicate the component functionality and then select the output value for which the majority of the components agree. For instance, one could implement the same functionality with three different circuits and then take majority value of the output bits. Your task is to implement the method buildMajorityOfThree in gatetasks. scala which should return a "majority of three" selection gate from the three input gates. For example, if the three inputs are 0, 0, and 1, then we must output 0 because 0 occurs in two inputs, which form the majority over the minority of 1, which occurs in only one input.

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Please use Scala to solve this question
 
package gatetasks

 

import tinylog._

 

object factory:
  /**
   Returns a gate containing the eXclusive OR of the two input gates
   */
  def buildXOR(in1 : Gate, in2: Gate) : Gate =
    // TASK 1: Return a gate which contains the exclusive or (XOR) of the two
    //         input gates.
    // Hints:  - Remember that gates can be combined to create new gates using
    //           logic operators || and && and negated using !
    //         - You can NOT check/compare the .value method of the gates as
    //           values are not set at the time you 'connect' the gates
    //           (remember that you are building a [very small] circuit)

 

    // Write your formula here:
    ???
  end buildXOR

 

  /**
    * Returns the majority state of gates in1, in2, in3
    */
  def buildMajorityOfThree(in1 : Gate, in2 : Gate, in3 : Gate) : Gate =
    // TASK 2: Return a gate which evaluates to
    // false - if two or three are false
    // true  - if two or three are true
    //
    // Hint: You are looking for a logic expression involving the three gates
    //       As always it will help to write the truth table or draw a diagram
    //       first

 

    // Write your formula here:
    ???
  end buildMajorityOfThree
Your tasks
Task 1: an exclusive-or gate
In addition to AND and OR gates, one commonly also needs an XOR gate (meaning eXclusive-OR). Its graphical presentation as well as
semantics are given in the following figure:
0
0
0
1
XOR
XOR
#i
XOR
[
XOR
0
1
Your task is to implement the method buildXOR in gatetasks. scala which should return a gate forming an XOR operation on the two input
gates.
Task 2: a majority-of-three gate
In many safety-critical applications one has to take into account that some of the components may fail for some reason.
One way to cope (to a limited degree) with failures is to replicate the component functionality and then select the output value for which the
majority of the components agree. For instance, one could implement the same functionality with three different circuits and then take majority
value of the output bits.
Your task is to implement the method buildMajorityOfThree in gatetasks. scala which should return a "majority of three" selection gate from
the three input gates. For example, if the three inputs are 0, 0, and 1, then we must output 0 because 0 occurs in two inputs, which form the
majority over the minority of 1, which occurs in only one input.
Transcribed Image Text:Your tasks Task 1: an exclusive-or gate In addition to AND and OR gates, one commonly also needs an XOR gate (meaning eXclusive-OR). Its graphical presentation as well as semantics are given in the following figure: 0 0 0 1 XOR XOR #i XOR [ XOR 0 1 Your task is to implement the method buildXOR in gatetasks. scala which should return a gate forming an XOR operation on the two input gates. Task 2: a majority-of-three gate In many safety-critical applications one has to take into account that some of the components may fail for some reason. One way to cope (to a limited degree) with failures is to replicate the component functionality and then select the output value for which the majority of the components agree. For instance, one could implement the same functionality with three different circuits and then take majority value of the output bits. Your task is to implement the method buildMajorityOfThree in gatetasks. scala which should return a "majority of three" selection gate from the three input gates. For example, if the three inputs are 0, 0, and 1, then we must output 0 because 0 occurs in two inputs, which form the majority over the minority of 1, which occurs in only one input.
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