Can you please send a solution for this? Thank you. Note: Use the proper representation for a vector, component vector, unit vector, and scalar quantities inyour solution. In this sample, all final answers in red ink are the format to be encoded in BB.Problem: 5 coordinates are given: A(-1, 4, 5), B(2, -1, -2), C(-6, -8, 3) in RCS; D(5, T, -12) in CCS; and E(8, 1/3,3n/2) in SCS. Let point O be the origin. Do the following:1. Convert the following coordinates given below:a. Coordinate C to CCS: C→ C(pc, ộc, zc)b. Coordinate C to SCS: C → C(rc, Oc, oc)c. Coordinate D to RCS: D→ D(XD, YD, ZD)d. Coordinate D to SCS: D → D(rd, OD, oo)ans: (10, –126.87,3)→ ans: (10.440, 73.30, – 126.87)→ ans: (-5,0, 12)— аns: (13, 157.38, 180)→ ans: (0, –6.928,4)— аns: (6.928, -90,4)E(XE, YE, ZE)f. Coordinate E to CCS: E → E(pe, DE, Ze)e. Coordinate E to RCS: E →2. Find the following vectors between two points:a. Vector directed from C to D. Label it as: RcD = Rxco + Ryco + RzcD in RCS→ ans: < 1,8, –15 >b. Vector directed from D to E. Label it as: RDE = RPDE + RODE + RZDE in CCS→ ans: < -5, 6.928, 16 >c. Vector directed from E to C. Label it as: RĘc = Rrec + Roec + RPec in SCS→ ans: < 0.428, 1.402, –6 >3. Find the distance between the two points given below:a. Cto D - ans: 17.029b. D to E → ans: 18.138с. E to C ans: 16.1764. Find the following unit vectors:→ ans: < 0.059,0.470,–0.881 >→- ans: < -0.276,0.382,0.882 >→ ans: < 0.069,0.227,–0.971 >a. aco in RCSb. aDe in CCSc. aɛc in SCS5. From the previous number, convert vector Rec SCS to CCS.→ ans:< 1.072, –6, –1 >→ ans: 60.506. The angle between segments AC and AB.7. The vector projection of the vector directed from A to B, to vector directed from O to C.→ ans: < -0.055, –0.073,0.028 >→ ans:5.5238. The area of the triangle defined by points A, B, and O.9. The unit vector perpendicular to the plane in which the triangle in #8 is located.→ ans: +< -0.272, 0.724, –0.634 >10. The volume of a parallelepiped if coordinates A, B, C, and O are its corners. → ans: 6711. If vector Rec is going to be transferred from point E to A, determine Rec as a function of its new→ ans: < -0.507,0.957,6.081 >components in SCS.12. If the tail of vector Rec is at A as in #11, determine the coordinate of its head in RCS.→ ans: (-7,2.928,4)

Since we are given with the multiple number of question and our guideline is solve first question…

your solution. In this sample, all final answers in red ink are the format to be encoded in BB. Problem: 5 coordinates are given: A(-1, 4, 5), B(2, -1, -2), C(-6, -8, 3) in RCS; D(5, T1, -12) in CCS; and 37/2) in SCS. Let point O be the origin. Do the following: 1. Convert the following coordinates given below: a. Coordinate C to CCS: C → C(pc, ¢c, zc) b. Coordinate C to SCS: C → C(rc, Oc, ̟c) c. Coordinate D to RCS: D → D(Xo, Yo, ZD) d. Coordinate D to SCS: D → D(ro, Op, ̟o) → ans: (10, –126.87, 3) - ans: (10.440,73.30, –126.87) → ans: (-5,0, 12) → ans: (13, 157.38, 180)

your solution. In this sample, all final answers in red ink are the format to be encoded in BB. Problem: 5 coordinates are given: A(-1, 4, 5), B(2, -1, -2), C(-6, -8, 3) in RCS; D(5, T1, -12) in CCS; and 37/2) in SCS. Let point O be the origin. Do the following: 1. Convert the following coordinates given below: a. Coordinate C to CCS: C → C(pc, ¢c, zc) b. Coordinate C to SCS: C → C(rc, Oc, ̟c) c. Coordinate D to RCS: D → D(Xo, Yo, ZD) d. Coordinate D to SCS: D → D(ro, Op, ̟o) → ans: (10, –126.87, 3) - ans: (10.440,73.30, –126.87) → ans: (-5,0, 12) → ans: (13, 157.38, 180)

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

ChapterP: Preliminary Concepts

SectionP.CT: Test

Problem 1CT

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