Can you please explain the solution attached below. salUseMLlemma to22| 1 5 1=20121=2 22²=2² dz|.2Rez4le 22 | = |ezrez | ≤ e 2:2 zieu12²-21 ≥ |2²|-1|2|= 121²2²-1214-2So= 222Z-2Rez|e²| = efe:еSoL= length of curve2Jtx r=L121=2show<2JT.e4M = ee4 JN4222ا۔2-2dz | ≤LM4e42JT e4

Here we have to explain the given attached solution.

Answered: Can you please explain the solution…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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5 = 4+ 3 9. Solve for x: x+4 X- 2
Can anyone explain how the answer come? I didn't understand much from the first step, why is there nothing on the left?
Please show step-by-step solution
Please check if there is more than one solution so I can see how to do it.
Akira is running around a circular track. Akira runs counterclockwise. From where he starts, it takes him 22 seconds to reach the easternmost point of the track. It takes him 95 seconds to run one complete lap.Bob starts running at the same time as Akira. Bob starts from the northernmost point and runs clockwise. Bob and Akira pass each other for the first time after 26 seconds. How long does Bob take to run one lap of the track? The answer to this question should be the amount of time in seconds rounded to four decimal places that it takes for Bob to run a complete lap around the circular track.
Select all solutions to (x – 2)=-16 口ェ=6 O I = -2. https://student.masteryconnect.com/#
Why is it important to obtain all multiple solutions when they exist?
13) The integer n = a) If n = 3 (mod 9), then what is x ? b) If n = 3 (mod 11), then what is x ? Hint for #13: 12700140x3243243 is missing the digit x. Consider the number 1234. By writing each digit in scientific notation, we have 1234 1 x 10³ +2× 10² +3 × 10¹ + 4 × 10⁰ Then notice that 10 = 1 (mod 9). When we reduce mod 9, we obtain 1234 1 x 10³ +2× 10² +3 x 10¹ + 4 x 10⁰ = = 1x 1³ + 2 x 1² + 3 × 1¹ + 4 × 1⁰ = 1+ 2+ 3+ 4 = 10 = 1 (mod 9). Since 10 = -1 (mod 11), when we reduce mod 11, we obtain 1234 1 x 10³ +2× 10² +3 x 10¹ + 4 x 10⁰ = = 1x (-1)³ +2× (-1)² +3 × (-1)¹ +4× (-1)⁰ = -1 + 2-3 + 4 = 2 (mod 11).
After answering Part 1 and 2, What do you find as the solution?
please solve this with clear text, as the last solution was not clear, also with full detail as well
the full answer wasn't shown in the solution box, please provide the rest
Please solve it with L-U factorization Thanks

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