Your Given Information:  teststatistic= 0.42 and p-value =0.6769. The null hypothesis is that the proportion of ball bearings with diameter values less than 2.20 cm in the existing manufacturing process is the same as the proportion in the new process. Because of this:  Null hypothesis: H0: p1=p2 Alternative hypothesis: H1: p1≠p2 The level of significance is α=0.05 As, the p-value is greater than the level of significance. So, we fail to reject the null hypothesis. That is null hypothesis cannot be rejected. And conclude that YES, there is sufficient evidence to say that the two population proportions are the same. Your Peer's Given Information: The null hypothesis states the number of ball bearings with diameter values less than 2.20 cm in the new manufacturing process is the same as the number in the old manufacturing process. The alternative hypothesis states the number of ball bearings with diameter values less than 2.20 cm in the new manufacturing process is not the same as the number in the old manufacturing process. The level of significance is 0.05: α = 0.05 The test statistic is -2.67, and because this is a two-tailed test, the p-value is 0.0077. Because the p-value is less than the level of significance, 0.0077 < 0.05, sufficient evidence exists to reject the null hypothesis stating that the number of ball bearings with diameter values less than 2.20 cm in both processes is the same.   Review your peers' analyses and address the following questions: How does your conclusion compare to theirs? Do they have the correct conclusion based on their P-value and the level of significance? Why or why not?

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Your Given Information:

 teststatistic= 0.42 and p-value =0.6769. The null hypothesis is that the proportion of ball bearings with diameter values less than 2.20 cm in the existing manufacturing process is the same as the proportion in the new process. Because of this:

 Null hypothesis: H0: p1=p2

Alternative hypothesis: H1: p1≠p2

The level of significance is α=0.05

As, the p-value is greater than the level of significance. So, we fail to reject the null hypothesis. That is null hypothesis cannot be rejected. And conclude that YES, there is sufficient evidence to say that the two population proportions are the same.

Your Peer's Given Information:

The null hypothesis states the number of ball bearings with diameter values less than 2.20 cm in the new manufacturing process is the same as the number in the old manufacturing process.

The alternative hypothesis states the number of ball bearings with diameter values less than 2.20 cm in the new manufacturing process is not the same as the number in the old manufacturing process.

The level of significance is 0.05: α = 0.05

The test statistic is -2.67, and because this is a two-tailed test, the p-value is 0.0077.

Because the p-value is less than the level of significance, 0.0077 < 0.05, sufficient evidence exists to reject the null hypothesis stating that the number of ball bearings with diameter values less than 2.20 cm in both processes is the same.

 

Review your peers' analyses and address the following questions:

  1. How does your conclusion compare to theirs?
  2. Do they have the correct conclusion based on their P-value and the level of significance? Why or why not?
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