Your computer runs an algorithm that has an order of growth as n*log(n) equal to the number of instructions to execute for data input of size n. If n = 10000 then number of instructions to execute for n = 10000 is: 40000 132877 10000 92103 9

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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18. Please just type answer.  Makes it easy on the both of us and saves times lol.

Your computer runs an algorithm that has an order of growth as n*log(n) equal to the
number of instructions to execute for data input of size n. If n = 10000 then number
of instructions to execute for n = 10000 is:
40000
132877
10000
92103
9
Transcribed Image Text:Your computer runs an algorithm that has an order of growth as n*log(n) equal to the number of instructions to execute for data input of size n. If n = 10000 then number of instructions to execute for n = 10000 is: 40000 132877 10000 92103 9
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Step 1

Introduction

The given question is a computational problem related to the analysis of algorithms. It involves determining the number of instructions required to execute an algorithm for a specific input size, given the algorithm's order of growth. This type of problem is commonly encountered in computer science and related fields, where it is important to understand the performance characteristics of algorithms as a function of input size. In this case, the order of growth of the algorithm is given as n log(n), and the input size is specified as n = 10000. 

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