Your answer is partially correct. For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=2.50 m, b=4.25 m, Pg= 45kN, and Pc = 90kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Answers: Ay= a 74.189 B Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Dy= i 59.21 B a PB a Pc KN Pc b KN D b D P x
Your answer is partially correct. For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M for any location in the beam. (Place the origin at point A.) Let a=2.50 m, b=4.25 m, Pg= 45kN, and Pc = 90kN. Construct the shear- force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. Answers: Ay= a 74.189 B Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.) Dy= i 59.21 B a PB a Pc KN Pc b KN D b D P x
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
![Part 3
Determine the bending moment acting at each of the following locations:
(a) x = 2 m
(b)x= 2.50 m (i.e., at point B)
(c) x = 4 m
(d) x = 5.00 m (i.e., at point C)
(e) x = 8 m
Note that x=0 at support A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2.
Answers:
(a) M=
i
(b) M= i
(c) M= i
(d) M= i
(e) M= i
kN-m
kN-m
kN-m
kN-m
kN-m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38f154bf-7439-45d6-8733-0d8ce23f56ed%2F7e147eab-e61a-41d8-99f7-2ffecf30ee86%2Ff365qgg_processed.png&w=3840&q=75)
Transcribed Image Text:Part 3
Determine the bending moment acting at each of the following locations:
(a) x = 2 m
(b)x= 2.50 m (i.e., at point B)
(c) x = 4 m
(d) x = 5.00 m (i.e., at point C)
(e) x = 8 m
Note that x=0 at support A. When entering your answers, use the bending-moment sign convention detailed in Section 7.2.
Answers:
(a) M=
i
(b) M= i
(c) M= i
(d) M= i
(e) M= i
kN-m
kN-m
kN-m
kN-m
kN-m
![Your answer is partially correct.
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M
for any location in the beam. (Place the origin at point A.) Let a=2.50 m, b=4.25 m, Pg= 45kN, and Pc = 90kN. Construct the shear-
force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO
exercise.
Answers:
Ay=
a
74.189
B
Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the
red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)
Dy= i 59.21
B
a
PB
a
Pc
KN
Pc
b
KN
D
b
D
P
x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38f154bf-7439-45d6-8733-0d8ce23f56ed%2F7e147eab-e61a-41d8-99f7-2ffecf30ee86%2F2v8dt5q_processed.png&w=3840&q=75)
Transcribed Image Text:Your answer is partially correct.
For the simply supported beam subjected to the loading shown, derive equations for the shear force V and the bending moment M
for any location in the beam. (Place the origin at point A.) Let a=2.50 m, b=4.25 m, Pg= 45kN, and Pc = 90kN. Construct the shear-
force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO
exercise.
Answers:
Ay=
a
74.189
B
Calculate the reaction forces Ay and Dy acting on the beam. Positive values for the reactions are indicated by the directions of the
red arrows shown on the free-body diagram below. (Note: Since Ax = 0, it has been omitted from the free-body diagram.)
Dy= i 59.21
B
a
PB
a
Pc
KN
Pc
b
KN
D
b
D
P
x
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